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icang [17]
3 years ago
10

Does anyone know how to solve a system of linear equations using elimination? I am having a hard time on how to do it for differ

ent types of equations.
Mathematics
1 answer:
Mariana [72]3 years ago
3 0
1. Multiply each equation so they end up with the same coefficient

2. Subtract your second equation from the first

3. Solve for one of the variables (I tend to solve an equation that only contains 2 variables if possible. So it would be if you have one question with x and y, solve for the easier one)

4. Substitute the variable you found in the least step into one of the other equations and find a second variable.

5. Substitute both variables you found into the last equation and there you should be left with x, y, and z :))

I hope this helped sksjsk if it didn’t I could write it out to hopefully help more :)
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If they traveled 2400 miles and the total driving time was 50 hours, divide 2400/50 in order to find how many miles they drove per hour.

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Gemma's mean speed on her drive home from Chicago is 59mph. If the total trip is 295 miles, how long should she expect the drive
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2 years ago
The formula for finding the perimeter of a rectangle is P = 2L + 2W. If a rectangle has a perimeter of 68 inches and the length
Artemon [7]

Answer:

Width = 10 inches

Step-by-step explanation:

Given the perimeter of a rectangle of 68 inches, and a length that is 14 inches longer than its width.

We can establish the following values to help us solve for the width of a rectangle:

Perimeter (P) = 68 inches

Length (L) = 14 + W inches

Width (W) = unknown

<h3 /><h3><u>Solve for the Width (W)</u></h3>

P =  2(L + W)  ⇒ This is the same as P = 2L + 2W, except that 2 is factored out from the right-hand side.

Divide both sides by 2:

\displaystyle\mathsf{\frac{P}{2}\:=\:\frac{2(L\:+\:W)}{2}}

\displaystyle\mathsf{\frac{P}{2}\:=L\:+\:W}

Substitute the value of the Perimeter and the length (L) into the formula:

\displaystyle\mathsf{\frac{68}{2}\:=14\:+W\:+\:W}

Combine like terms on the right-hand side, and simplify the left-hand side of the equation:

\displaystyle\mathsf{34\:=14\:+2W}

Subtract 14 from both sides:

34 - 14 = 14 - 14 + 2W

20 = 2W

Divide both sides by 2 to solve for the width (W):

\displaystyle\mathsf{\frac{20}{2}\:=\:\frac{2W}{2}}

W = 10 inches

Therefore, the width of the rectangle is 10 inches.

<h3 /><h3><u>Double-check:</u></h3>

Verify whether the derived value for the width is correct:

P = 2L + 2W

68 = 2(14 + 10) + 2(10)

68 = 2(34) + 20

68 = 48 + 20

68 = 68 (True statement).  

Thus, the length of the rectangle is 34 inches, and the width is 10 inches.

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3 years ago
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