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Mathematics

1 answer:

alex41 [277]3 years ago

7 0

Answer:

They are similar.

Step-by-step explanation:

They have same angles.

Triangle =180°

49+82+49=180

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A fair coin is tossed, and a marble is chosen from the bag whose contents are shown below. 3 red marbles, 3 blue marbles, and 4

Firlakuza [10]

Answer:

3/20

Step-by-step explanation:

Red = 3

Blue = 3

Green = 4

Total = 3+3+4 = 10

Pr (red) = 3/10

Pr blue) = 3/10

Pr (green) = 4/10

Where Pr = probability

You either have a head or a tail when tossing a coin

Probability of having head = 1/2

Probability of having tail = 1/2

The probability of the coin landing heads up and blue marble = Probability of head ×Pr (blue)

= 1/2 × 3/10

the probability of the coin landing heads up and blue marble = 3/20

6 0

3 years ago

Read 2 more answers

SOMEONE PLEASE HELP!!

lesya692 [45]

First you need the size of an angle QPR = B = 180° - 123°
Lenght of QP = 10cm
QR = x
QP = r
x² = r² + r² - 2r² × cosB

8 0

2 years ago

Read 2 more answers

How do you simplify:<br><br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B%28125%20%5E%7B2%7D%20%7D%20%29%20%20%20%5E%7B%20-%20

Nady [450]

Answer:

$\huge\boxed{\sqrt{(125^2)^{-\frac{1}{3}}}=\dfrac{1}{5}}$

Step-by-step explanation:

$\sqrt{(125^2)^{-\frac{1}{3}}}\qquad\text{use}\ (a^n)^m=(a^m)^n\\\\=\sqrt{\left(125^{-\frac{1}{3}\right)^2}\qquad\text{use}\ \sqrt{a^2}=a\ \text{for}\ a\geq0\\\\=125^{-\frac{1}{3}}\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}\\\\=\dfrac{1}{125^\frac{1}{3}}\qquad\text{use}\ a^\frac{1}{n}=\sqrt[n]{a}\\\\=\dfrac{1}{\sqrt[3]{125}}=\dfrac{1}{5}\qquad\text{because}\ 5^3=125$