Answer:
a-The present value of revenue in the first year is $61,085.92.
b-The total time it would take to pay for its price is 2.44 years of 29.33 months.
Explanation:
a-
Let the function of the revenue earned is given as
![S(t)=\left \{ {{66000t+38000} {\ \ 0The present value is given as [tex]PV=\int\limits^a_b {S(t)e^{-rt}} \, dt](https://tex.z-dn.net/?f=S%28t%29%3D%5Cleft%20%5C%7B%20%7B%7B66000t%2B38000%7D%20%7B%5C%20%5C%200%3C%2Fp%3E%3Cp%3EThe%20present%20value%20is%20given%20as%20%3C%2Fp%3E%3Cp%3E%5Btex%5DPV%3D%5Cint%5Climits%5Ea_b%20%7BS%28t%29e%5E%7B-rt%7D%7D%20%5C%2C%20dt)
Here
- a and b are the limits of integral which are 0 and 1 respectively
- r is the rate of interest which is 5% or 0.05
- S(t) is the function of value which is
![S(t)=\left \{ {{66000t+38000} {\ \ 0So the equation becomes[tex]PV=\int\limits^0_1 {S(t)e^{-0.05t}} \, dt\\PV=\int\limits^{0.5}_0 {(66000t+38000)e^{-0.05t}} \, dt+\int\limits^{1}_{0.5}{(71000)e^{-0.05t}} \, dt\\PV=\int\limits^{0.5}_0 {(66000t)e^{-0.05t}} \, dt+\int\limits^{0.5}_0 {(38000)e^{-0.05t}} \, dt+\int\limits^{1}_{0.5}{(71000)e^{-0.05t}} \, dt\\PV=8113.7805+18764.4669+34207.6751\\PV=61085.9225](https://tex.z-dn.net/?f=S%28t%29%3D%5Cleft%20%5C%7B%20%7B%7B66000t%2B38000%7D%20%7B%5C%20%5C%200%3C%2Fli%3E%3C%2Ful%3E%3Cp%3ESo%20the%20equation%20becomes%3C%2Fp%3E%3Cp%3E%5Btex%5DPV%3D%5Cint%5Climits%5E0_1%20%7BS%28t%29e%5E%7B-0.05t%7D%7D%20%5C%2C%20dt%5C%5CPV%3D%5Cint%5Climits%5E%7B0.5%7D_0%20%7B%2866000t%2B38000%29e%5E%7B-0.05t%7D%7D%20%5C%2C%20dt%2B%5Cint%5Climits%5E%7B1%7D_%7B0.5%7D%7B%2871000%29e%5E%7B-0.05t%7D%7D%20%5C%2C%20dt%5C%5CPV%3D%5Cint%5Climits%5E%7B0.5%7D_0%20%7B%2866000t%29e%5E%7B-0.05t%7D%7D%20%5C%2C%20dt%2B%5Cint%5Climits%5E%7B0.5%7D_0%20%7B%2838000%29e%5E%7B-0.05t%7D%7D%20%5C%2C%20dt%2B%5Cint%5Climits%5E%7B1%7D_%7B0.5%7D%7B%2871000%29e%5E%7B-0.05t%7D%7D%20%5C%2C%20dt%5C%5CPV%3D8113.7805%2B18764.4669%2B34207.6751%5C%5CPV%3D61085.9225)
So the present value of revenue in the first year is $61,085.92.
b-
The time in which the machine pays for itself is given as
The present value is set equal to the value of machine which is given as
$160,000 so the equation becomes:
So the total time it would take to pay for its price is 2.44 years of 29.33 months.
Answer:
The accumulated present value is $67,518.99.
Explanation:
Investment opportunities that require a series of payments of a fixed amount for a specific number of periods are known as annuities.
The Present Value of this annuity can be calculated as :
Fv = $0
n = 30
r = 4.2 %
Pmt = - $4,000
P/ yr = 1
Pv = ?
Using a financial calculator, the Present Value (PV) of the annuity is $67,518.9948 or $67,518.99.
Explanation:
The journal entries are as follows:
On July 1
Prepaid Insurance A/c Dr $20,700
To Cash A/c $20,700
(Being prepaid insurance is paid)
On December 31
Insurance expense A/c Dr $
To Prepaid insurance A/c $1,110
(Being the insurance expense is recorded)
The insurance expense is shown below:
= $20,700 ÷ 3 years × 6 months ÷ 12 months
= $3,450
Answer:
Option (B) If the market rate of interest is 10%, the bonds will issue at a discount
Explanation:
Interest rate risk is defined as the risk changing which, interest rates will affect bond prices. When current interest rates are greater than a bond's coupon rate, the bond will be sold below its face value at a discount. When interest rates are less than the coupon rate, the bond can be sold at a premium--higher than the face value.
Sohan invested Rs 80000 in the beginning of his firm. After six months, Mohan invested Rs. 65,000 to become a partner. Sohan put his money into investments for 12 months, while Mohan made investments for 6 months. They made a total profit of Rs. 20,000 after a year. The portion of Sohan in the profit that he made is 14222.
One way to assess a company's success is through its profit. Its simplest definition is the sum that remains after deducting all expenses from all revenues. The remaining funds, or your profits, can either be retained by the company and reinvested to fund future expansion, or they can be given as a draw or dividends to shareholders.
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