Area of the parabolic region = Integral of [a^2 - x^2 ]dx | from - a to a =
(a^2)x - (x^3)/3 | from - a to a = (a^2)(a) - (a^3)/3 - (a^2)(-a) + (-a^3)/3 =
= 2a^3 - 2(a^3)/3 = [4/3](a^3)
Area of the triangle = [1/2]base*height = [1/2](2a)(a)^2 = <span>a^3
ratio area of the triangle / area of the parabolic region = a^3 / {[4/3](a^3)} =
Limit of </span><span><span>a^3 / {[4/3](a^3)} </span>as a -> 0 = 1 /(4/3) = 4/3
</span>
Answer:
f(2) = g(2)
General Formulas and Concepts:
<u>Alg I</u>
- Reading a Cartesian Plane
- Identifying Coordinates
- Solutions of systems of equations
Step-by-step explanation:
We see from the graph that f(x) and g(x) intersect at x = 2. Therefore, the point at x = 2 would be equivalent in both graphs/be a solution to both equations.
Therefore, f(2) must equal g(2), as they intersect each other at that point and have the same value of 0.
Answer:
Length = 10.5units,Area = 68.25 unit²
Step-by-step explanation:
Perimeter =34 units
Width =6.5 units
Perimeter = l+l+w+w
Where l= length and w= width
34 = l + l + 6.5+ 6.5
34.= 2l + 13
Subtract 13 from both sides
2l = 34 - 13
2l = 21
Divide both sides by 2
L= 21/2
Length = 10.5units
If we are to find the area.
Area = length x width
Area = 10.5 × 6.5
Area = 68.25 unit²
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I’ve attached a photo, with the instructions. Hope it helps. If you have any questions don’t hesitate to ask
Answer:
what do you mean?
Step-by-step explanation:
