The equation is saying that -3x+10=5x-8. Once you get all the same terms on one side, you get 18=8x. That would end up being a decimal number, instead of a whole number. The x values would either have to be -4x or 6x in order to make the problem equal
Answer:
Option C.
Step-by-step explanation:
The given logarithmic equation is
It can be written as
![[\because log_ax=y\Leftrightarrow x=a^y]](https://tex.z-dn.net/?f=%5B%5Cbecause%20log_ax%3Dy%5CLeftrightarrow%20x%3Da%5Ey%5D)
Now, to check whether is a true solution or not. Substitute in the LHS of given equation.
![[\because log_aa^x=x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20log_aa%5Ex%3Dx%5D)
Hence, is a true solution because 
.
Therefore, the correct option is C.
Answer:
2/7
Step-by-step explanation:
There are 22 (12 + 10) total students in the class. That means that the chance of the first student picked being a girl is 12/22.
Now, we must calculate the chance of the next student to be picked <em>also </em>being a girl - however, there is a trap here! Remember that since a girl has been picked, the total student pool has decreased to 21 and and the total number of girls has decreased to 11. This means the new chance of girl being picked is 11/21.
To find the probability of both these events happening in conjunction, these fractions must be multiplied. 12/22 * 11/21 = 132/462, which simplifies to 2/7.
Answer:
2625 cubic meters
Step-by-step explanation:
the volume of a rectangle is V = length x width x height (depth in this case)
so, 50m x 30m x 1.75m = 2625m^3
Answer:
4, 6, 1
Step-by-step explanation:
We can solve this problem using a system of equations:
1) a + b + c = 11
2) 2a + 5b + 6c = 44
3) 4a - b = 10
First, we can substitute the value of b from equation #3 into equation #1:
b = 4a - 10
a + (4a - 10) + c = 11
5a - 10 + c = 11
5a + c = 21
c = 21 - 5a
Now, we can plug the values of b and c into equation #2, as b and c are represented in terms of a:
2a + 5(4a - 10) + 6(21 - 5a) = 44
2a + 20a - 50 + 126 - 30a = 44
-8a + 76 = 44
-8a = -32
a = 4
b = 4a - 10 = 4(4) - 10 = 6
c = 21 - 5a = 21 - 5(4) = 1
