Answer:
Observation
Explanation:
The scientific process typically starts with an observation (often a problem to be solved) that leads to a question. Let's think about a simple problem that starts with an observation and apply the scientific method to solve the problem.
Hope it's helps.
The most important factor to include in the plan of care is option Monitor blood glucose levels frequently.
<h3>Why monitor the
blood glucose?</h3>
It is said to be good for a nurse to educate their client after DKA on things that they need to know regarding their care.
They should tell them information on the need for home glucose and it is one that needs to be monitored for at least two to four times per day.
One can also informs the client in regards to when the sickness can and they should know that the presence of urine ketones shows that DKA has taken place already.
Therefore, The most important factor to include in the plan of care is option Monitor blood glucose levels frequently.
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A nurse is assisting a client with diabetes mellitus who is recovering from diabetic ketoacidosis (DKA) to develop a plan to prevent a recurrence. Which is most important to include in the plan of care?
1.Test urine for ketone levels.
2.Eat six small meals per day.
3.Monitor blood glucose levels frequently.
4.Receive appropriate follow-up health care.
Answer:
¿Qué es la circuncisión femenina. Si la circuncisión (es decir, la eliminación del pene en la carne) en el extremo llamado casi salvador de la población masculina del globo de la infección por VIH, Aquí hay un punto de corte del clítoris y los labios menores se invierte la situación.
Explanation:
Answer:
25 quarters, 23 dimes, and 0 nickels.
Explanation:
Let n = number of nickels, q = number of quarters, and d = number of dimes
n + d = q - 2
n + d + q = 48
8.05 = .25q + .1d + .05n
so
(q-2) + q = 48
2q = 50
q = 25
Using that q value:
n + d = q - 2 --> n + d = 25 - 2 --> n + d = 23 --> n = 23 - d
Using that n value and q value:
8.05 = .25(23) + .1d + .05(23 - d)
8.05 = 5.75 + .1d + 1.15 - .05d
2.30 = 1.15 + .05d
1.15 = .05d
23 = d
Using that d value and q value:
n + d + q = 48 --> n + 23 + 25 = 48
n + 48 = 48
n = 0
Therefore there are 25 quarters, 23 dimes, and 0 nickels.
Checking that with:
8.05 = .25q + .1d + .05n
8.05 = .25(23) + .1(23) + .05(0)
8.05 = 5.75 + 2.30 + 0
8.05 = 8.05 ✓
