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Cloud [144]
3 years ago
10

Why am i smart esfcobqagd

Mathematics
1 answer:
katen-ka-za [31]3 years ago
7 0

Answer:

Because you pay attention in school. Thank you for the points!!

Step-by-step explanation:

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Mindy buys 12 cupcakes. Nine of the cupcakes have chocolate frosting. What fraction of the cupcakes have vanilla frosting?
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1 fourth which as a fraction would look like:

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Write 796.384 in expanded form
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700+90+6+0.3+0.08+0.004
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Find the length of the line joining the points A(-2,10) and B(-8,2)
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Length of the line

= \sqrt{((-2)-(-8))^{2}+(10-2)^{2}  }

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=\sqrt{100}

= 10

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Which expression shows 2/3 + 4/5 written using a common denominator
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Segments AB , CD , and EF intersect at point O, points A, E, C and points B, F, D are collinear so that AO ≅ OB , CO ≅ OD . Prov
katovenus [111]

If points A, E and C are colinear, then they lie on the same line. The same statement you can say about points B, F and D.

1. Consider triangles AOC and BOD. In these triangles:

  • AO≅OB (given);
  • CO≅OD (given);
  • ∠AOC≅∠BOD (as vertical angles).

Thus, ΔAOC≅ΔBOD by SAS Postulate (If any two corresponding sides and their included angle are the same in both triangles, then the triangles are congruent). Corresponding parts of congruent triangles are congruent, then

  • AC≅BD;
  • ∠ACO≅∠BDO;
  • ∠CAO≅∠DBO.

Since angles ACO and BDO are alternate interior angles between lines AE and BF with transversal CD and these angles are congruent, then lines AE and BF are parallel.

This gives you that

  • ∠CEO≅∠OFD;
  • ∠ECO≅∠ODF.

2. Consider triangles ECO and FDO. In these triangles

  • ∠CEO≅∠OFD (previous proof);
  • CO≅OD (given);
  • ∠ECO≅∠ODF (previous proof).

Therefore, ΔECO≅ΔFDO by AAS Postulate (if two angles and the non-included side one triangle are congruent to two angles and the non-included side of another triangle, then these two triangles are congruent). Then CE≅FD.

3. Note that

  • AE=AC+CE;
  • BF=BD+DF.

Since AC≅BD and CE≅DF, then AE=AC+CE=BD+DF=BF.

7 0
3 years ago
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