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2 years ago

Please help!!! 10 point for it :)

Mathematics

1 answer:

choli [55]2 years ago

8 0

Answer: aight bro I only know B which is 90°. If it’s drawn to scale use a protractor. Is there more info, maybe I can help

Step-by-step explanation:

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HELP PLS Steven keeps

Archy [21]

Answer:

Option (3)

Step-by-step explanation:

Steven has created a box plot to record the number of students who attended the science club meeting.

In a box plot, initial dot represents the minimum number and extreme point represents the maximum number.

From the graph attached,

Maximum number of students who attended the meeting are 32.

Therefore, Option (3) will be the correct option.

5 0

2 years ago

Find the indicated probability or percentage for the sampling error. The distribution of weekly salaries at a large company is r

Flauer [41]

Answer:

The probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 80 employees will be at most $75 is 0.9297.

Step-by-step explanation:

According to the Central Limit Theorem if we have a non-normal population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.

Then, the mean of the distribution of sample means is given by,

$\mu_{\bar x}=\mu$

And the standard deviation of the distribution of sample means is given by,

$\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}$

The information provided is:

$\mu=\$1000\\\sigma=\$370\\n=80$

As n = 80 > 30, the central limit theorem can be used to approximate the sampling distribution of sample mean weekly salaries.

Let $\bar X$ represent the sample mean weekly salaries.

The distribution of $\bar X$ is: $\bar X\sim N(\$1000,\ \$41.37)$

Now we need to compute the probability of the sampling error made in estimating the mean weekly salary to be at most $75.

The sampling error is the the difference between the estimated value of the parameter and the actual value of the parameter, i.e. in this case the sampling error is, $|\bar X-\mu|= 75$ .

Compute the probability as follows:

$P(-75$

$=P(-1.81$

Thus, the probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 80 employees will be at most $75 is 0.9297.

3 0

3 years ago

15 G F H 4) What is the value of x? A) 10 B) 12 C) 15 D) 17

coldgirl [10]

Answer:

C) 15

Step-by-step explanation:

This is an isosceles triangle (two of the three angles are equal) so two of the sides are also equal. x is the same length as 15.

5 0

2 years ago

Students arrived at the museum at 1:15pm.They stayed at the museum for 2hours and 51 minutes.At what time did the students leave

guapka [62]

1:15 2 hours is 3:15

3 0

3 years ago

PLEASE HELP!! Identify the minium value of the function

timama [110]

Because this is a positive parabola, it opens upwards, like a cup, and the vertex dictates what the minimum value of the function is. In order to determine the vertex, I recommend completing the square. Do that by first setting the function equal to 0 and then moving the 9 to the other side by subtraction. So far: $x^2+6x=-9$ . Now, to complete the square, take half the linear term, square it, and add that number to both sides. Our linear term is 6. Half of 6 is 3 and 3 squared is 9. So add 9 to both sides. $x^2+6x+9=-9+9$ . The right side reduces to 0, and the left side simplifies to the perfect square binomial we created while completing this process. $(x+3)^2=0$ . Move the 0 back over and the vertex is clear now. It is (-3, 0). Therefore, 0 is the minimum point on your graph. The first choice above is the one you want.

3 0

3 years ago