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3 years ago

I will give extra points please help

Mathematics

1 answer:

weqwewe [10]3 years ago

6 0

Answer:

Step-by-step explanation:

<u>3 </u>+ 4 = 7.

So, therefor, x = 3

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2x + 4 < 10 I really need help on this

Leona [35]

Answer:

x < 3

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Is anyone able to figure this out, I can't do this

katrin [286]

Answer:

C. √2 - 1

Step-by-step explanation:

If we draw a square from the center of the large circle to the center of one of the small circles, we can see that the sides of the square are equal to the radius of the small circle (see attached diagram)

Let r = the radius of the small circle

Using Pythagoras' Theorem $a^2+b^2=c^2$

(where a and b are the legs, and c is the hypotenuse, of a right triangle)

to find the diagonal of the square:

$\implies r^2 + r^2 = c^2$

$\implies 2r^2 = c^2$

$\implies c=\sqrt{2r^2}$

So the diagonal of the square = $\sqrt{2r^2}$

We are told that the radius of the large circle is 1:

⇒ Diagonal of square + r = 1

$\implies \sqrt{2r^2}+r=1$

$\implies \sqrt{2r^2}=1-r$

$\implies 2r^2=(1-r)^2$

$\implies 2r^2=1-2r+r^2$

$\implies r^2+2r-1=0$

Using the quadratic formula to calculate r:

$\implies r=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$\implies r=\dfrac{-2\pm\sqrt{2^2-4(1)(-1)}}{2(1)}$

$\implies r=\dfrac{-2\pm\sqrt{8}}{2}$

$\implies r=-1\pm\sqrt{2}$

As distance is positive, $r=-1+\sqrt{2}=\sqrt{2}-1$ only

5 0

3 years ago

Read 2 more answers

Dy/dx= y^4 and y(2)= -1. Y(-1)=

cupoosta [38]

It looks like you're asked to find the value of y(-1) given its implicit derivative,

$\dfrac{dy}{dx} = y^4$

and with initial condition y(2) = -1.

The differential equation is separable:

$\dfrac{dy}{y^4} = dx$

Integrate both sides:

$\displaystyle \int \frac{dy}{y^4} = \int dx$

$-\dfrac1{3y^3} = x + C$

Solve for y :

$\dfrac1{3y^3} = -x + C$

$3y^3 = \dfrac1{-x+C} = -\dfrac1{x + C}$

$y^3 = -\dfrac1{3x+C}$

$y = -\dfrac1{\sqrt[3]{3x+C}}$

Use the initial condition to solve for C :

$y(2) = -1 \implies -1 = -\dfrac1{\sqrt[3]{3\times2+C}} \implies C = -5$

Then the particular solution to the differential equation is

$y(x) = -\dfrac1{\sqrt[3]{3x-5}}$

and so

$y(-1) = -\dfrac1{\sqrt[3]{3\times(-1)-5}} = \boxed{\dfrac12}$

6 0

3 years ago

I need help finding the solution

Ilya [14]

<h3>Answer: 226 degrees</h3>

=====================================================

Explanation:

Notice the tickmarks on the segments in the diagram. This tells us that chords DC and CB are the same distance from the center. It furthermore means that DC and CB are the same length, and arcs DC and CB are the same measure

arc DC = arc CB

12x+7 = 18x-23

12x-18x = -23-7

-6x = -30

x = -30/(-6)

x = 5

---------------------

Use this x value to find the measure of arcs DC and CB

arc DC = 12x+7 = 12*5+7 = 67
arc CB = 18x-23 = 18*5-23 = 67

We get the same measure for each, which helps confirm we have the correct x value.

The two arcs in question add to 67+67 = 134 degrees. This is the measure of arc DCB. Subtract this from 360 to get the answer

arc DAB = 360-(arc DCB) = 360-134 = 226 degrees

I'm using the idea that (arc DCB) + (arc DAB) = 360 since the two arcs form a full circle.

7 0

3 years ago

What is 7 times ten to the first place

algol [13]

700

Step-by-step explanation:

you just take 10 times it by itself 1 time you get 100 then you times it by 7

7 0

3 years ago