Answer:
C++ code is given below
Explanation:
#include <iostream>
#include <cctype>
#include <string.h>
#include <cstring>
#include <sstream>
using namespace std;
struct Car {
public:
char reportingMark[5];
int carNumber;
string kind;
bool loaded;
string destination;
};
void input(Car *);
void output(Car *);
int main() {
Car *T = new Car;
input(T);
output(T);
delete T;
return 0;
}
void input(Car *T)
{
string str, s;
cout << " Enter the reporting mark as a 5 or less character uppercase string: ";
cin >> str;
for (int i = 0; i < str.length(); i++)
T->reportingMark[i] = toupper(str[i]);
cout << " Enter the car number: ";
cin >> T->carNumber;
cout << " Enter the kind: ";
cin >> T->kind;
cout << " Enter the loaded status as true or false: ";
cin >> s;
istringstream(s) >> boolalpha >> T->loaded;
if (T->loaded == true) {
cout << " Enter the destination: ";
cin.ignore();
getline(cin, T->destination);
}
else
T->destination = "NONE";
}
void output(Car *T)
{
cout << " Reporting Mark: " << T->reportingMark;
cout << " Car Number: " << T->carNumber;
cout << " Kind: " << T->kind;
cout << " Loaded Status: " << boolalpha << T->loaded;
cout << " Destination: " << T->destination << " ";
}
The answer for this question is true
Answer:
See Explanation Below
Explanation:
The new code segment is
int feb = 28;
if ((year % 4) == 0 && (year % 100) != 0) // assume that year is an integer with a valid year value
{
System.out.println("This is a leap year");
feb = 29;
}
Assume year = 2020, the assigned value of feb is 29;
Reason below;
At line 2 of the new code segment, two conditions are tested both of which must be satisfied.
1. year % 4 == 0
2020 % 4 = 0
0 = 0 (True)
2. year % 100 != 0
2020 % 100 != 0
20 != 0 (True)
Since both conditions are true, the value assigned to feb will be 29 and
"This is a leap year" will be printed without the quotes
C. schedule.
Outlook adds your appointment to your schedule folder.
