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Dima020 [189]
3 years ago
5

27 = a + 11 one and two step equations

Mathematics
1 answer:
Bingel [31]3 years ago
6 0
27=a+11
To keep the equation balanced minus 11 from both sides to get 16=a
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Konrad raised $75.50 for his football team. He raised 151% of his fundraising goal how much more then his fundraising did Konrad
Colt1911 [192]

Answer:

He raised $25.50 over his fund raising goal

Step-by-step explanation:

Here, we want to calculate his fund raising goal.

Let his fund raising goal be $x

We are told that he raised 151% of his fundraising goal;

Thus,

mathematically;

151% of x = 75.5

151/100 * x = 75.5

151x = 100 * 75.5

151x = 7550

x = 7550/151

x = $50

So the amount he raised over his fund raising goal will be $75.50 - $50 = $25.50

8 0
3 years ago
Find m∠USW if m∠USW = 7x - 34 and m∠TSR = 4x + 9.
nikitadnepr [17]

In this question, it is given that the measurement of angles USW and TSR are 7x-34 and 4x+9 .

First we have to find the relationship between those two angles .

And these angles are vertical opposite angles which are congruent .

Therefore

m \angle USW = m \angle TSR

7x-34 = 4x+9
\\
3x = 43
\\
x = 14.33

Therefore measurement of angle USW is

=7(14.33)-34 =66.31 degree

5 0
3 years ago
Lines b and c are parallel what is the measure of angle 6?
elena-s [515]

Answer:

54 degrees

Step-by-step explanation:

If these two lines are parallel, than angles 1 and 7 are supplementary.

13x+9+5x+9=180

18x+18=180

x+1=10

x=9

Angle 6 and 7 are vertical angles, so they are equal. Therefore, angle 6 is:

5x+9=5(9)+9=54

Hope this helps!!

3 0
3 years ago
What is the sign of 3x y3xy3, x, y when x>0x>0x, is greater than, 0 and y<0y<0y, is less than, 0?
jekas [21]

Answer:

Negative

Step-by-step explanation:

We\ have\ to\ find\ sign\ of\ 3xy^3\\\\x>0\ and\ y0,y

4 0
4 years ago
Read 2 more answers
(Brainliest to the person that get its right)
oksian1 [2.3K]
<h3>Answer: Choice B</h3>

c^2-2cd+d^2 = (c-d)^2

We can verify this with the following steps

(c-d)^2 = (c-d)(c-d)

(c-d)^2 = c(c-d) - d(c-d)

(c-d)^2 = c^2-cd-cd+d^2

(c-d)^2 = c^2-2cd+d^2

6 0
2 years ago
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