Explanation:
Addition of fractions can be accomplished using the formula ...
a/b + c/d = (ad +bc)/(bd)
Usually, you are asked to find the common denominator and rewrite the fractions using that denominator. It is not necessary, but it can save a step in the reduction of the final result. Here, we'll use the formula, then reduce the result to lowest terms.
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13. 5/6 +9/11 = (5·11 +6·9)/(6·11) = 109/66 = 1 43/66
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14. 7/20 -5/8 = (7·8 -20·5)/(20·8) = -44/160 = -11/40
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15. 1/5 -1/12 = (1·12 -5·1)/(5·12) = 7/60
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Dividing fractions can be accomplished different ways. I was taught to multiply by the inverse of the divisor. ("Invert and multiply.") Here, that means the problem (2/7) / (1/13) can be rewritten as ...
(2/7) × (13/1) . . . . . where 13/1 is the inverse of 1/13.
You can also express the fractions over a common denominator. In that case, the quotient is the ratio of the numerators. Perhaps a little less obvious is that you can express the fractions using a common numerator. Then the quotient is the inverse of the ratio of the denominators: (2/7) / (2/26) = 26/7. (You can see how this works if you "invert and multiply" the fractions with common numerators. Those numerators cancel.)
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16. (2/7)/(1/13) = 2/7·13/1 = 26/7 = 3 5/7
Answer:
millicoulomb
Step-by-step explanation:
millicoulomb is 1*10^-3 Coulombs
Answer:
The optimal Hedge Ratio is 0.7305.
Step-by-step explanation:
Optimal Hedge ratio is given as
![HR_{optimal}=\epsilon_{correlation} \times \frac{\sigma_{current}}{\sigma_{future}}](https://tex.z-dn.net/?f=HR_%7Boptimal%7D%3D%5Cepsilon_%7Bcorrelation%7D%20%5Ctimes%20%5Cfrac%7B%5Csigma_%7Bcurrent%7D%7D%7B%5Csigma_%7Bfuture%7D%7D)
Here
- HR_optimal is the Hedge Ratio for the next 6 months which is to be calculated.
- ε_correlation is the correlation coefficient relating the assets and futures contract whose value is give as $0.86.
- σ_current is the standard deviation of the semiannual changes of the wheat which is given as $0.79
- σ_future is the standard deviation of the changes in the future over the same time period which is given as $0.93
So the Hedge Ratio is given as
![HR_{optimal}=\epsilon_{correlation} \times \frac{\sigma_{current}}{\sigma_{future}}\\HR_{optimal}=0.86 \times \frac{0.79}{0.93}\\HR_{optimal}= \$0.7305](https://tex.z-dn.net/?f=HR_%7Boptimal%7D%3D%5Cepsilon_%7Bcorrelation%7D%20%5Ctimes%20%5Cfrac%7B%5Csigma_%7Bcurrent%7D%7D%7B%5Csigma_%7Bfuture%7D%7D%5C%5CHR_%7Boptimal%7D%3D0.86%20%5Ctimes%20%5Cfrac%7B0.79%7D%7B0.93%7D%5C%5CHR_%7Boptimal%7D%3D%20%5C%240.7305)
So the optimal Hedge Ratio is 0.7305.
Answer:
the answer is 399
Step-by-step explanation:
19 times 10 is 190. 19 times 10 again is 190. Add 190 together and you get 380. then, you add the final 19 and you get 399.
If the price of the car is $22,500 in 2000. Then the value of the car in 2011 with a decay of 5% every year is $12,798.
<h3>What is an exponent?</h3>
Exponential notation is the form of mathematical shorthand which allows us to write complicated expressions more succinctly. An exponent is a number or letter is called the base. It indicates that the base is to raise to a certain power. X is the base and n is the power.
A car was purchased in 2000 for $22,500.
It has depreciated at a rate of 5% per year.
Then the price of the car in 2011 will be
The decay function is modeled as
![\rm A = P(1-r)^t](https://tex.z-dn.net/?f=%5Crm%20A%20%3D%20P%281-r%29%5Et)
The number of years has been passed is 11.
Then we have
![\rm A = 22,500(1-0.05)^{11}\\\\A = \$ \ 12798](https://tex.z-dn.net/?f=%5Crm%20A%20%3D%2022%2C500%281-0.05%29%5E%7B11%7D%5C%5C%5C%5CA%20%3D%20%5C%24%20%5C%2012798)
More about the exponent link is given below.
brainly.com/question/5497425
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