Answer=0.3
1/10 of 3.0 is 0.3
3.0*(1/10)=0.3
Answer:
36900
Step-by-step explanation:
It's a linear function with equation P(t)=900+600*t. P(60)=900+600*60=36900
Any point in that shaded area is a solution
(0,0) is a solution
(-1,-1) is a solution
(-3,3) is a solution
etc
Answer:
Step-by-step explanation:
You aren't able to figure out an exact number of either footballs or basketballs because you don't have enough information for that, but you do have enough to get an expression for one in terms of the other, which I imagine is the point here. We know that for every 1 basketball sold, we sold 2.5 footballs, so the algebraic expression for that is
1 bball = 2.5 fballs
This gives us the number of bballs in terms of fballs but we want the number of fballs in terms of bballs, so solve that expression for fballs:
1 fball = 1/2.5 bballs
or, in words, for every single football sold, 2/5 of a basketball was sold. Sounds silly, but I think your teacher is trying to get you to figure out how to express one thing in terms of another so you can use the expressions in solving story problems.
:/
The general equation for a circle,

, falls out of the Pythagorean Theorem, which states that the square of the hypotenuse of a right triangle is always equal to the sum of the squares of its legs (you might have seen this fact written like

, where <em>a </em>and <em>b</em> are the legs of a right triangle and <em>c </em>is its hypotenuse. When we fix <em /><em>c</em> in place and let <em>a </em>and <em>b </em>vary (in a sense, at least; their values are still dependent on <em>c</em>), the shape swept out by all of those possible triangles is a circle - a shape defined by having all of its points equidistant from some center.
How do we modify this equation to shift the circle and change its radius, then? Well, if we want to change the radius, we simply have to change the hypotenuse of the triangle that's sweeping out the circle in the first place. The default for a circle is 1, but we're looking for a radius of 6, so our equation, in line with Pythagorus's, would look like

, or

.
Shifting the center of the circle is a bit of a longer story, but - at first counterintuitively - you can move a circle's center to the point (a,b) by altering the x and y portions of the equation to read: