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Fiesta28 [93]
3 years ago
13

On a school trip to a theme park, 4 busses each carry 70 students.

Mathematics
1 answer:
DanielleElmas [232]3 years ago
7 0

Answer:

165 Students Have No Made Plans For Lunch.

Step-by-step explanation:

According To the Question,

  • Given,On a school trip to a theme park, 4 busses each carry 70 students Then Total Number Of Students on a trip is 70×4=280 Students.
  • And,35% of the students are bringing their own lunch. Thus,35% Of 280 Students is 98 Students. Then Remaining 182 Students not bring their own lunch.

Now, 17 of the students are buying lunch when they get to the theme park. Thus students Who have not made plans for lunch is 182-17⇒165Students

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Answer:

3x

Step-by-step explanation:

-(x-1) +5 = 2(x+3) - c

C is the unknown term

Distribute the negative sign and the 2

-x+1 +5 = 2x+6 -c

Combine like terms

-x+6 = 2x +6-c

Solve for c

Add x to each side

-x+x +6 = 2x+x +6-c

6 = 3x+6 -c

Add c to each side

6+c = 3x +6 -c+c

c+6 = 3x+6

Subtract 6 from each side

c+6-6 = 3x+6-6

c = 3x

When c = 3x, the two sides of the equation are equal, and the solutions are infinite.

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3 years ago
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PLEASE HELP WITH MY MATH. SCIENTIFIC NOTATION PROBLEM.
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Answer:


Step-by-step explanation:

a) 8.23 x 10^5 move the decimal over 5 places, 319000000 is 319 million move the decimal over until there is one number on the left side --> 3.19 x 10^8

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This scale drawing shows a parking lot. What is the length of the longer side of the actual lot?
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630 m c

Step-by-step explanation:

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3 years ago
a wooden box has external dimensions 40 cm by 34 cm by 30 cm. if the wood is 1 cm thick how many cm3 of wood is used in it ?​
Westkost [7]

Answer:

6752 cm³ of wood

Step-by-step explanation:

V = 40cm×34cm×30cm = 40800 cm³

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V - v = 40800cm³ - 34048cm³ = 6752 cm³ of wood

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3 years ago
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The blood cholesterol levels of men aged 55 to 64 are approximately normally distributed with mean 222 mg/dl and standard deviat
tatiyna

Answer:

It is provided that 10% of the men aged 55 to 64 have cholesterol level <u>270 mg/dl</u> or higher.

Step-by-step explanation:

Let <em>X</em> = blood cholesterol levels of men aged 55 to 64 years.

The random variable <em>X</em> follows a Normal distribution with mean <em>μ</em> = 222 mg/dl and standard deviation <em>σ</em> = 37 mg/dl.

It is provided that 10% of the men aged 55 to 64 have cholesterol level <em>x</em> mg/dl or higher.

Compute the value of <em>x</em> as follows:

P(X\geq x)=0.10\\P(\frac{X-\mu}{\sigma}\geq \frac{x-222}{37})=0.10\\P(Z\geq z)=0.10\\1-P(Z

Use the <em>z</em>-table to compute the value <em>z</em> for the probability 0.90.

The value of <em>z</em> is 1.29.

Compute the value of <em>x</em> as follows:

z=\frac{x-\mu}{\sigma}\\1.29=\frac{x-222}{37} \\x=222+(1.29\times37)\\=269.73\approx270

Thus, 10% of the men aged 55 to 64 have cholesterol level 270 mg/dl or higher.

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3 years ago
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