Here, the given equation is,
x^2+y^2+px+6y-3=0
By copairing it with x^2+y^2+2gx+2fy+c=0, we get,
2g=p or, g=p/2
2f=6 or, f=3
c=-3
now the radius is,
r^2=g^2+f^2-c
or, 4^2=(p/2)^2 +3^2 -(-3)
or, 16= p^2/4 +9+3
or, 16-9-3=p^2/4
or p^2/4=4
or, p^2=4×4
or p^2=4^2
or p=4
therefore the rewuired value of p is 4.
If you have only white shirts in your closet, the probability of pulling a red shirt would be 0/x, where x represents the total number of shirts in the closet.
The correct question is
<span>The length of a rectangle if the length is twice the size of the width increased by 1 is it one of the following answers:
A) l= 2w-1
B) l= 2w+1
C) l= 3w
D) none of the choices given
Let
l--------------> </span>length of a rectangle
w-------------> width of a rectangle
we know that
if the length is twice the size of the width increased by 1
l=2w+1
the answer is the option B) l= 2w+1
Answer: 4 .
_____________
n/2 = 5 - 3 ;
_______________
n/2 = 2 ;
_______________
n = 2*2 ;
_______________
n = 4 .
_______________
What is the solution (not answer) to (not too) x^2 - 3x + 5 = 0?
This is a quadratic equation. Two possible approches to solving it are
1) quadratic formula, and
2) completing the square.
Let's use the quadratic formula:
a=1, b= -3, c = 5
Then
-(-3) plus or minus sqrt( [-3]^2 - 4(1)(5) )
x = --------------------------------------------------------
2
3 plus or minus sqrt(9-20) 3 plus or minus i*sqrt(11)
= ------------------------------------- = ------------------------------------
2
Please note: These are complex roots, due to the " i ".
