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3 years ago

Question 6

Mathematics

1 answer:

Sunny_sXe [5.5K]3 years ago

6 0

Answer:

D. 246 grams

Step-by-step explanation:

invnorm(.95, 240, 3) is around 244 and the question is asking for the least weight of a bag in the top 95%, so the smallest number within

a. 234

b. 240

c. 243

d. 246

e. 248

is d.

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Please help if you are good at math :( thank you

ValentinkaMS [17]

Answer:

your answer will be

A)(6,10)

B)(2,12)

C)(4,4)

Step-by-step explanation:

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3 years ago

Please help me ASAP!!!! <br> 30 points

nekit [7.7K]

Answer:

Step-by-step explanation:

f(x) = 2x-1

g(x) =x^2 +3

f°g(x) = means put g(x) in for x into the function f(x)

f(g(x)) = 2 (g(x)-1

=2(x^2 +3) -1

Distribute

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4 0

4 years ago

In triangle ABC, the measure of angle B is 50 degrees.

victus00 [196]

Answer:

Step-by-step explanation:

Possible values of A and C are 60° and 70° (since their sum must give is 130°)

Another possible values are 55° and 75°

8 0

3 years ago

The price of a gallon of milk follows a normal distribution with a mean of $3.20 and a standard deviation of $0.10. What proport

Inga [223]

Answer:

$P(x$

Step-by-step explanation:

Mean $\=x=\$3.20$

Standard deviation $\sigma =\$0.10$

Estimated price $y=\$3.12$

Generally the equation for P(x<3.12) is mathematically given by

$P(x$

Since from Z table

$P(x$

Therefore the proportion of the milk vendors that have prices that were less than $3.12 per gallon is

$P(x$

6 0

3 years ago

Consider the function f(x)=x2e4x. f(x) has two inflection points at x = C and x = D with C≤D where C is and D is Finally for eac

fredd [130]

Answer:

the inflection points are

$x = -0.85, -0.14$

So,

$C = -0.85 \\D = -0.14$

It is concave down at the intervals

$(-\infty , -0.85] \cup [-0.14,\infty)$

And it would be concave up at

$(-0.85 , -0.14)$

Step-by-step explanation:

Remember that to find inflection points you need to find where

$f''(x) = 0$

Since

$f(x) = x^2 e^{4x}$

Then using the product and the chain rule you have that

$f'(x) = 2e^{4x} x(2x+1)$

And then, using again the chain rule and the product rule you have that

$f''(x) = 2e^{4x} (8x^2 +8x+1)$

Therefore you have to solve the equation

$8x^2 +8x+1 = 0$

Using the quadratic equation you get that there are two solutions, so the inflection points are

$x = -0.85, -0.14$

So,

$C = -0.85 \\D = -0.14$

Now remember that a function is concave up if the derivative is greater than zero and concave down if the derivative is less than zero. Therefor you have to solve these inequalties

$8x^2 +8x+1 < 0 \\8x^2 +8x+1 \geq 0$

And you would get that is concave down at the intervals

$(-\infty , -0.85] \cup [-0.14,\infty)$

And it would be concave up at

$(-0.85 , -0.14)$

8 0

3 years ago