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2 years ago

I need help because I'mnot Smart and don't know how to do this.

Mathematics

2 answers:

Galina-37 [17]2 years ago

5 0

Answer:

Area= 480 because 8x6x10=480

Perimeter= 24 because 8+6+10=24

Step-by-step explanation:

valentina_108 [34]2 years ago

5 0

Answer:

Area = 48

Perimiter = 24

Step-by-step explanation:

Area is L x W

So it would be 6 x 8 = 48

Perimiter is all sides added together so it would be 6 + 10 + 8 =24

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What are two different way of factoring -3x-9? Select all that apply

Ghella [55]

Options:

A. –3(x + 3)

B. 3(x + 3)

C. 3(–x – 3)

D. –3(x – 3)

Answer:

A and C

Step-by-step explanation:

Given

$-3x - 9$

Required

Factorize

The options are not given; So, I'll answer on a general term

$-3x - 9$

Express -9 as -3 * 3

$-3x - 9 = -3x - 3 * 3$

Then factorize 3 out of the expression as:

$-3x - 9 = 3(-x - 3)$

Another way is to factor -3 out of the expression as:

$-3x - 9 = -3x - 3 * 3$

$-3x - 9 = -3(x + 3)$

3 0

2 years ago

Write each improper fraction as a mixed number: 93/12

yuradex [85]

Answer:

The answer would be 7 3/4

Step-by-step explanation:

4 0

2 years ago

The two intervals (114.9, 115.7) and (114.6, 116.0) are confidence intervals (computed using the same sample data) for μ = true

kenny6666 [7]

Answer:

115.3 hertz

Step-by-step explanation:

For either interval, the value of the sample mean is given by the average of the lower and upper bound of the confidence interval. Since both intervals were constructed by using the same sample, both values should be equal.

For the first interval:

$M=\frac{114.9 + 115.7}{2} \\M=115.3\ hertz$

For the second interval:

$M=\frac{114.6 + 116.0}{2} \\M=115.3\ hertz$

4 0

2 years ago

What is the value of g(-4)? HINT: It's not A. A. -1 B. 27 C. -5 D. 1

GalinKa [24]

Answer: C
I hope this helps

6 0

2 years ago

Read 2 more answers

Which of the following represents the zeros of f(x) = 2x3 − 5x2 − 28x + 15?

likoan [24]

$\mathrm{Use\:the\:rational\:root\:theorem}$

$a_0=15,\:\quad a_n=2$

$\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:3,\:5,\:15,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1,\:2$

$\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:3,\:5,\:15}{1,\:2}$

$-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3$

$\mathrm{Compute\:}\frac{2x^3-5x^2-28x+15}{x+3}\mathrm{\:to\:get\:the\:rest\:of\:the\:eqution:\quad }2x^2-11x+5$

$=\left(x+3\right)\left(2x^2-11x+5\right)$

$Factor: 2x^2-11x+5$

$2x^2-11x+5=\left(2x^2-x\right)+\left(-10x+5\right)$

$=x\left(2x-1\right)-5\left(2x-1\right)$

$2x^3-5x^2-28x+15=\left(x+3\right)\left(x-5\right)\left(2x-1\right)$

$\left(x+3\right)\left(x-5\right)\left(2x-1\right)=0$

$\mathrm{Using\:the\:Zero\:Factor\:Principle:}$

thus zeros of f(x) is

$x=-3,\:x=5,\:x=\frac{1}{2}$

5 0

2 years ago

Read 2 more answers

I need help because I'mnot Smart and don't know how to do this.​

I need help because I'mnot Smart and don't know how to do this.