Part A:
Given a square with sides 6 and x + 4. Also, given a rectangle with sides 2 and 3x + 4
The perimeter of the square is given by 4(x + 4) = 4x + 16
The area of the rectangle is given by 2(2) + 2(3x + 4) = 4 + 6x + 8 = 6x + 12
For the perimeters to be the same
4x + 16 = 6x + 12
4x - 6x = 12 - 16
-2x = -4
x = -4 / -2 = 2
The value of x that makes the <span>perimeters of the quadrilaterals the same is 2.
Part B:
The area of the square is given by

The area of the rectangle is given by 2(3x + 4) = 6x + 8
For the areas to be the same

Thus, there is no real value of x for which the area of the quadrilaterals will be the same.
</span>
X=8 because add 11 to both sides and it becomes 28=3.5x and divide both sides by 3.5 so x=8
Answer:
Question 2: Radios remaining is the dependent variables and the hours are the Independent variables
8 alligator because is u divide 48/5 you get 40 and the remaining that r awake is 8
(3, -2) satisfies both equations. 3-2=1, and -3-2=-5.