The answer is I believe b=70
9. 1/3+(x+20)+(x-10)+40=360 10. 1/2x+1/2x+(x-15)+(x-25)+100=540
1/3+2x+50=360 4x+60=540
(3/1) 1/3+2x=300(3/1) 4x/4=480/4
2x=300 X=120
————
2
W=150
Answer:
46 is d I'm not sure for 47 but I think it's c not sure tho
Surface area of a sphere = 4πr²
Surface area of the sphere = 4π(0.8)² = 8.0 ft²
Volume of a sphere = 4/3 πr³
Volume of the sphere = 4/3 π(0.8)³ = 2.1 ft³
Answer: Surface area = 8.0 ft² and volume - 2.1 ft³ (Answer C)
Answer:
Total area = 237.09 cm²
Step-by-step explanation:
Given question is incomplete; here is the complete question.
Field book of an agricultural land is given in the figure. It is divided into 4 plots. Plot I is a right triangle, plot II is an equilateral triangle, plot III is a rectangle and plot IV is a trapezium, Find the area of each plot and the total area of the field. ( use √3 =1.73)
From the figure attached,
Area of the right triangle I = 
Area of ΔADC = 
= 
= 
= 
= 
= 30 cm²
Area of equilateral triangle II = 
Area of equilateral triangle II = 
= 
= 73.0925
≈ 73.09 cm²
Area of rectangle III = Length × width
= CF × CD
= 7 × 5
= 35 cm²
Area of trapezium EFGH = 
Since, GH = GJ + JK + KH
17 = 
12 = 
144 = (81 - x²) + (225 - x²) + 2
144 - 306 = -2x² + 
-81 = -x² + 
(x² - 81)² = (81 - x²)(225 - x²)
x⁴ + 6561 - 162x² = 18225 - 306x² + x⁴
144x² - 11664 = 0
x² = 81
x = 9 cm
Now area of plot IV = 
= 99 cm²
Total Area of the land = 30 + 73.09 + 35 + 99
= 237.09 cm²