There would be 1 real zero and two complex zeros
this is a binomial problem: p = 0.7 and q = 0.3
a) (0.7)^6
b) (6C4)(0.7)^4(0.3)^2
c) Pr ( at least 4) = Pr(4) + Pr(5) + Pr(6) = (6C5)(0.7)^5(0.3) + (0.7)^6
d) Pr (no more than 4) = 1 - Pr(at least 4) = 1 - (answer from c)
Slope is delta y over delta x, so -51/3 = -17
Answer:
y = -2/3 x + 23/3
Explanation:
The general formula of the linear equation is:
y = mx + c
where:
m is the slope
c is the y-intercept
1- getting the slope:
We are given that the line we are looking for is parallel to the line
y = -2/3 x + 3
This means that the slope of the two lines are equal. Comparing the general formula with the given line, we would find that the slope of the given line is -2/3. This means that the slope of the line we are looking for is also -2/3
The equation of the line now becomes:
y = -2/3 x + c
2- getting the value of c:
To get the value of c, we will use a point that belongs to the line (7,3), substitute in the equation and solve for c as follows:
y = -2/3 x + c
3 = (-2/3)(7) + c
3 = -14/3 + c
c = 3 + 14/3
c = 23/3
Based on the above, the equation of the line we are looking for is:
y = -2/3 x + 23/3
Hope this helps :)
