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Anarel [89]
3 years ago
5

Find the value of a/b/c if a=1/3, b=1/2, c=1/6

Mathematics
1 answer:
densk [106]3 years ago
8 0

Answer: The answer is 0.1111111111111

Step-by-step explanation:

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Please help me with this question, and show the work . Thank you so much !!!!
jenyasd209 [6]
Step 1 is wrong it should be: 2x - 3x - 1=3
6 0
3 years ago
The math club is sponsoring a bake sale.If their goal is to raise at least $200,how many pies must they sell at $4.00 each in or
Tems11 [23]
The math club must sell 50 pies in order to reach the goal of 200 dollars
4 0
3 years ago
Seventy-three percent means the same as
Gwar [14]
Seventy-three percent is the same as 73% , .73 , and \frac{73}{100} .
4 0
3 years ago
Read 2 more answers
The standard IQ test has a mean of 97 and a standard deviation of 17. We want to be
densk [106]

Let's call our estimate x. It will be the average of n IQ scores. Our average won't usually exactly equal the mean 97.  But if we repeated averages over different sets of tests, the mean of our estimate the average would be the same as the mean of a single test,

μ = 97

Variances add, so the standard deviations add in quadrature, like the Pythagorean Theorem in n dimensions.  This means the standard deviation of the average x is

σ = 17/√n

We want to be 95% certain

97 - 5 ≤ x ≤ 97 + 5

By the 68-95-99.7 rule, 95% certain means within two standard deviations. That means we're 95% sure that

μ - 2σ ≤ x ≤ μ + 2σ

Comparing to what we want, that's means we have to solve

2σ = 5

2 (17/√n) = 5

√n = 2 (17/5)

n = (34/5)² = 46.24

We better round up.

Answer: We need a sample size of 47 to be 95% certain of being within 5 points of the mean

6 0
3 years ago
Please can someone help me
Sidana [21]
If the answer is D. the equation to represent the ages of students is:
n + n+1 + n+2 = 45
it is showing that  n is the age of one student and the other student has age one year more than the first one and third students has age of 2 years more than first student and one year greater than the second student. if we solve this equation for the value of n, we get;
3n + 3 = 45
3n = 45 -3
3n = 42
n = 14
so the age of one student is 14, second student 15 and third student 16 years.
and if we add there ages, 14 + 15 + 16 = 45
4 0
3 years ago
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