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Nataly [62]
3 years ago
10

Select the expression that is equivalent to x + x + y × y × y. Question 11 options: (a)x^2 + 3y (b)2x + 3y (c)x^2 + y^3 (d)2x +

y^3
Mathematics
1 answer:
beks73 [17]3 years ago
7 0

x+x+y.y.y = 2x+y^3 ( y cube)

So, The answer is (d)

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Can someone please help me?
Ede4ka [16]

Ok so their are 36 people that didn't need gel for there hair. so when you multiply 36 x 5 (because each cut costs 5 bucks) you get an answer of 180. so hold on to that and since their are 16 people that asked for gel you would need to first multiply 5 and 10% which gives you 0.5 so when you multiply 5.5 (because when you multiplied the 10% with the 5 you should get .5) times 16 you should get an answer of 88. when you add 180 with 88 you get an answer of 268. Ur welcome couuld u mark this brainlist plzzzzz


3 0
3 years ago
There is a number that if you multiply it by 4 first, and then subtract 10 from the result, you get 14. What's the number.
polet [3.4K]
It's 6. 6 times 4 is 24, and 24 minus 10 is 14
6 0
4 years ago
What are the possible rational roots of the polynomial equation?<br><br> 0=2x7+3x5−9x2+6
RoseWind [281]

Answer: \pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}

Step-by-step explanation:

We can use the Rational Root Test.

Given a polynomial in the form:

a_nx^n +a_{n- 1}x^{n - 1} + … + a_1x^1 + a_0 = 0

Where:

- The coefficients are integers.

- a_n is the leading coeffcient (a_n\neq 0)

- a_0 is the constant term a_0\neq 0

Every rational root of the polynomial is in the form:

\frac{p}{q}=\frac{\pm(factors\ of\ a_0)}{\pm(factors\ of\ a_n)}

For the case of the given polynomial:

2x^7+3x^5-9x^2+6=0

We can observe that:

- Its constant term is 6, with factors 1, 2 and 3.

- Its leading coefficient is 2, with factors 1 and 2.

 Then, by Rational Roots Test we get the possible rational roots of this polynomial:

\frac{p}{q}=\frac{\pm(1,2,3,6)}{\pm(1,2)}=\pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}

5 0
3 years ago
Find the distance between the two points rounding to the nearest tenth (if necessary).
Vaselesa [24]

Hey there! I'm happy to help!

Imagine the line that is created when you connect the two points (the distance between the two points).

You can create a right triangle where this distance is the hypotenuse where the two legs are the change in x and y. So, if you take those changes in x and y, you can use the Pythagorean Theorem (a²+b²=c²) to find the distance between the two points, which is the hypotenuse.

Our change in x is 9 because 9-0 is 9.

We square it

9²=81

Our change in y is 5 as -1-(-6) or -1+6 is 5.

5²=25

We add these.

81+25=106

We square root and round to the nearest tenth.

√106≈10.3

So, our distance is 10.3.

This Pythagorean Theorem method actually gives us a formula called the distance formula that you can use to find the distance between points.

\sqrt{(x_{2} -x_{1})^2+(y_{2}-y_{1})^2}

Have a wonderful day and keep on learning! :D

8 0
3 years ago
PLEASE HELP MEE ITS URGENT
Inessa05 [86]
Scale factor is 1/2
7 0
3 years ago
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