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3 years ago

13

Worth 30 points. Help a homie out

1 answer:

Sauron [17]3 years ago

8 0

Answer:

Multiply the second equation by -3 to get -3x - 9y = -30.

Step-by-step explanation:

When eliminating, you need to find a term with the negative of that term to combine so that they cancel each other out. An example would be 3x in the first equation and (-3x) in another equation so that when added, it becomes: 3x-3x = 0.

In the second equation, you see that there is already an x there and you just need to make it become (-3x). Thus, you multiply the entire second equation by -3 to make -3x. Once you have done that, you can combine the two equations and eliminate 3x from the first equation.

3x + 5y = 30

-3x - 9y = -30

3x + 5y -3x - 9y = 30 + (-30)

0 - 4y = 30 - 30

-4y = 0

<em>You can find y and then x later on from here. </em>

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Read 2 more answers

What is the positive slope of the asymptote of (y+11)^2/100-(x-6)^2/4=1? The positive slope of the asymptote is .

VladimirAG [237]

Answer:

the positive slope of the asymptote = 5

Step-by-step explanation:

Given that:

$\frac{(y+11)^2}{100} -\frac{(x-6)^2}{4} =1$

Using the standard form of the equation:

$\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}= 1$

where:

(h,k) are the center of the hyperbola.

and the y term is in front of the x term indicating that the hyperbola opens up and down.

a = distance that indicates how far above and below of the center the vertices of the hyperbola are.

For the above standard equation; the equation for the asymptote is:

$y = \pm \frac{a}{b} (x-h)+k$

where;

$\frac{a}{b}$ is the slope

From above;

(h,k) = 11, 100

$a^2$ = 100

a = $\sqrt{100}$

a = 10

$b^2 =4$

b = $\sqrt{4}$

b = 2

$y = \pm \frac{10}{2} (x-11)+2$

$y = \pm 5 (x-11)+2$

y = 5x-53 , -5x -57

Since we are to find the positive slope of the asymptote: we have

$\frac{a}{b}$ to be the slope in the equation $y = \pm \frac{10}{2} (y-11)+2$

$\frac{a}{b}$ = $\frac{10}{2}$

$\frac{a}{b}$ = 5

Thus, the positive slope of the asymptote = 5

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2 years ago

Find the two values that are both 6 units away from 3.

MrMuchimi

3 +6=9 and 3-6 =-3. that’s all you need to do

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2 years ago

Solve |x-6|+8=17.<br> A. x=-15 and x=3 B. x=15 and x=-15 C. x=15 and x=-3 D. x=-15 and x=-3

Tasya [4]

Answer:

A. x=-15 and x=3

Step-by-step explanation:

|x+6|+8=17

|x+6|=9

-1(x+6)=9 x+6=9

-x-6=9 x=3

-x=15

x=-15

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2 years ago