The factorized form of the polynomial 6x³ – 12x² + 7x – 14 is (6x²+7)(x–2).
<h3>What is a factor?</h3>
A factor of n is a number which when multiplied by another number gives us the number n.
In order to factorize the polynomial 6x³ – 12x² + 7x – 14, we need to take the common terms out of the given polynomial, therefore, the polynomial can be factorized as,
Taking the common term 6x² out from the first two terms, and then 7 from the next two terms, therefore, the polynomial can be written as
Hence, the factorized form of the polynomial 6x³ – 12x² + 7x – 14 is (6x²+7)(x–2).
Learn more about Factors:
brainly.com/question/6810544
Well you are given the roots.
if we have 3 it would.have to be x^3. So something like:
y = ax^3 + bx^2 + cx + d
this could.also be written:
y = (x + a) (x + b) (x + c)
when you are able to write it like this, we know that the opposite of a, b, and c are roots. this is because if we can make any of the insides of the 3 parenthesis equal 0 then y = 0 and that x.is a root. Well if we know the 3 roots that x will be then we just have to figure out the a, b, and c. So let's plug our roots in.
y = (-1 + a) (-5 + b) (-3 + c)
now we have to make each parenthesis equal 0 to find what a, b, and c should be. It is obvious a = 1 to make.that one zero and b = 5 and c = 3. So we know a, b, and c. now let's plug.those into our first equation.
y = (x + 1) (x + 5) (x + 3)
this is your equation. You can multiply out if necessary
Answer:
b. x + (x + 2) + (x + 4) = 39
Step-by-step explanation:
<u>Definitions</u>
- Integer: a whole number that can be positive, negative or zero.
e.g. ..., -3, -2, -1, 0, 1, 2, 3, ... - Odd number: an integer that when divided by two leaves a remainder (so not a multiple of 2). For example, 1, 3, 5, 7 are all positive odd numbers.
- Consecutive: following one after the other in order.
<u>The sum of three consecutive odd integers</u>
Let x be the first odd integer.
As there is a <u>difference of 2</u> between <u>consecutive odd integers</u>, the next odd integer after x will be (x + 2).
Therefore, the next odd integer after (x + 2) will be (x + 2) + 2 = (x + 4).
So "the sum of three consecutive odd integers is thirty-nine" is:
x + (x + 2) + (x + 4) = 39
<u>To solve</u>
⇒ x + (x + 2) + (x + 4) = 39
⇒ x + x + 2 + x + 4 = 39
⇒ 3x + 6 = 39
⇒ 3x = 33
⇒ x = 11
Therefore, the three consecutive odd numbers are 11, 13 and 15.
