Answer:
Yes there is sufficient evidence.
Null hypothesis; H_o ; μ = 445
Alternative hypothesis; H_o ; μ ≠ 445
Step-by-step explanation:
The null hypothesis states that there is no difference in the test which is denoted by H_o. However, the sign of null hypothesis is denoted by the signs of = or ≥ or ≤.
Meanwhile, the alternative hypothesis is one that defers from the null hypothesis. This therefore implies a significant difference in the test. Thus, the signs of alternative hypothesis is denoted by; < or > or ≠.
Now, the question we have is a two tailed test. Thus;
The null hypothesis is;
bag filling machine works correctly at the 445 gram setting which is;
H_o ; μ = 445
The alternative hypothesis is;
bag filling machine works incorrectly at the 445 gram setting which is;
H_o ; μ ≠ 445
18x can also be expressed as:
= 2x * (4+5)
= 2x * 9
= 18x
ANSWER: 2x * (4 + 5)
Hope this helps! :)
Answer:
A)σ = 15.37 miles per hour
B) σ = 55.10 miles per hour
C) 39.73 miles per hour
Step-by-step explanation:
Formula for standard deviation is;
σ = √(Σ(x - μ)²)/(n - 1)
A) For large wild cats;
μ = Σx/n = (70 + 40 + 30 + 40 + 35 + 35 + 35 + 35 + 10)/9 = 36.67
σ = √((70 - 36.67)² + (40 - 36.67)² + (30 - 36.67)² + (40 - 36.67)² + (35 - 36.67)² + (35 - 36.67)² + (35 - 36.67)² + (35 - 36.67)² + (10 - 36.67)²)/(9 - 1)
σ = √236.1139
σ = 15.37
B) For various birds;
μ = Σx/n = (218 + 106 + 97 + 56 + 66 + 39 + 55 + 32 + 54 + 20 + 25 + 25)/12
μ = 66.0833
σ = √((218 - 66.0833)² + (106 - 66.0833)² + (97 - 66.0833)² + (56 - 66.0833)² + (66 - 66.0833)² + (39 - 66.0833)² + (55 - 66.0833)² + (32 - 66.0833)² + (54 - 66.0833)² + (20 - 66.0833)² + (25 - 66.0833)² + (25 - 66.0833)²)/(12 - 1)
σ = √3035.72
σ = 55.10
C) difference in standard deviations = 55.10 - 15.37 = 39.73 miles per hour
Answer:
The distribution of scores on this final exam is left-skewed.
Step-by-step explanation:
We use the Pearson Mode Skewness to solve this question. It states that:
If the median is higher than the mean, the distribution is left-skewed.
If the median is lower than the mean, the distribution is right-skewed.
If the median is the same as the mean, the distribution is symmetric.
In this problem, we have that:
Median = 74
Mean = 70
Median higher than the mean
So the distribution of scores on this final exam is left-skewed.
The third one should be correct, “IMO” if the second person that answers agrees it’s 100%, I’ve had a question similar but I’m not sure exactly.. sorry tho, please lmk if somethings wrong “I will reply I’m not like those kids trying to get coins”
