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Virty [35]
3 years ago
14

The original price of a ski jacket was $220. It was on sale at a 25% discount. Arianna had a coupon for an additional 10% off th

e sale price.
What price did Arianna pay for the ski jacket?
Mathematics
1 answer:
Simora [160]3 years ago
5 0
$143
add the two discounts of 25 and 10 percent. then your item will be 65% of the price now.
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Hi, the answer is K but can anyone show why
dlinn [17]

Let's do 51 and 52.

51. The contrapositive has the same truth value as the original statement. That's opposed to the converse, which may or may not be true independent of the original statement.

The contrapositive of IF P THEN Q is IF not Q THEN not P.  They're equivalent.  Here that's If the cat is not female then it is not tricolor.

Answer: C

52.  

(x^3)^{(4-b^2)}=1

x^{3(4-b^2)} = 1

For the statement to be true, the exponent must be zero:

3(4-b^2) = 0

b^2 = 4

b = \pm 2

Both positive 2 and negative 2 have a square of 4.

Answer: K

By the way, usually we assume 0^0=1 so the restriction that x \ne 0 isn't really necessary.  Think of the definition of a polynomial or the binomial expansion:

\displaystyle f(x)=\sum_{k=0}^n a_k x^k

\displaystyle(x+y)^n=\sum_{k=0}^n {n \choose k} x^{k}y^{n-k}

For these common equalities to work when x=0 we need to define 0^0=1


3 0
4 years ago
What is the Y-intercept of (y-3)=1/3(x+4)
Debora [2.8K]

Answer: 0,13/3

Step-by-step explanation: Hope this helps - Lily ^_^

3 0
3 years ago
A 5 piece pack of gun cost $.85. An 8 pack of gum costs $1.20. How much cheaper per piece is the 8 piece pack?
babunello [35]
Each piece in the 5 pack cost: .17
Each piece in the 8 pack cost: .15

So the answer would be 2 cents cheaper
8 0
3 years ago
E(5,3) and F (2,-1) are two vertices of a square EFGH and H is in the x-axis .Find the coordinates of H and G. Please need answe
timurjin [86]

Answer:

coordinates of H = (1, 0)

Coordinates of G = ( - 3.6, -2) or (5.6, -2)

Step-by-step explanation:

E(5,3) and F (2,-1) are two vertices of a square EFGH and H is in the x-axis.

Let the coordinates of H is (x, 0) and G is (a, b).

The length of side EF is

EF = \sqrt{(5 -2)^2 + (3 +1)^2} = 5

So,

EH = \sqrt{(5 -x)^2 + (3 -0)^2} = 5\\\\(5 -x)^2+ 9 = 25\\\\5 - x = 4\\\\x = 1

And

GH = \sqrt{(a -x)^2+ b^2} = 5\\\\(a -1)^2+ b^2 = 25\\\\a^2 + b^2 + 1 - 2 a = 25\\\\a^2 + b^2 - 2a = 24 .... (1)

Now

FG = \sqrt{(a -2)^2+ (b +1)^2} = 5\\\\(a -2)^2+ (b+1)^2 = 25\\\\a^2 + b^2 + 2b - 2 a = 20\\   ..... (2)

Solving (1) and (2)

b = - 2 ,

a = \frac{2 \pm\sqrt{4 + 80}}{2}\\\\a = \frac{2 \pm 9.2}{2}\\\\a = - 3.6, 5.6

3 0
3 years ago
What error did the manager make
Sedbober [7]
Ur mom ur mom ur mom ur mom
5 0
3 years ago
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