S/4-6.8=-9.8
S/4= -9.8+6.8
S/4= -3
S=-3*4
S= -12
x = –6
Solution:
Given expression is ![\sqrt[3]{x-2}+5=3](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx-2%7D%2B5%3D3)
.
Step 1: Isolate the radical by subtracting 5 from both sides of the equation.
![\Rightarrow\sqrt[3]{x-2}+5-5=3-5](https://tex.z-dn.net/?f=%5CRightarrow%5Csqrt%5B3%5D%7Bx-2%7D%2B5-5%3D3-5)
![\Rightarrow\sqrt[3]{x-2}=-2](https://tex.z-dn.net/?f=%5CRightarrow%5Csqrt%5B3%5D%7Bx-2%7D%3D-2)
Step 2: Cube both sides of the equation to remove the cube root.
![\Rightarrow(\sqrt[3]{x-2})^3=(-2)^3](https://tex.z-dn.net/?f=%5CRightarrow%28%5Csqrt%5B3%5D%7Bx-2%7D%29%5E3%3D%28-2%29%5E3)
Cube and cube root get canceled in left side of the equation.
Step 3: To solve for x.
Add 2 on both sides of the equation.
Hence the solution is x = –6.
Answer:
True
Step-by-step explanation:
repeating decimal is also known as recurring decimal. It is form of representation of fractional number in which numbers after decimal periodically gets repeated.
Example 1/9 = 0.1111 where number one gets repeated infinitely
another common example is 1/7 = 0·142857 142857 14...
here digits 142857 repeated periodically after decimal.
As given in question "A repeating decimal has a never-ending pattern of the same digits" is consistent with definition of repeating decimal hence statement is true.
Answer:
a= -2
b= 1
c= 5
b^2-4ac= 41
The quadratic function will have 2 real number zeros
Step-by-step explanation:
Edguinity
