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2 years ago

Find the area of this circle

Mathematics

2 answers:

Black_prince [1.1K]2 years ago

6 0

Answer:

12.56

Step-by-step explanation:

How I remember the area formula of a circle is with the word PIZZA. Pizza are you know is a circle and I break down the word. PI= 3.14, ZZ= Z² (but in books and class they will use r², I'm replacing that r with a z), A= area.

Using my formula

PIZZA

Pi=3.14

ZZ= 2²=4

A= area

3.14*4=area

12.56=area

anygoal [31]2 years ago

5 0

Area of a circle is pie times the radius to the second power.

So the answer is 4 time pie

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NEED HELP ASAP !!! Please

Sergio039 [100]

I do not know what is your question.

3 0

3 years ago

Which statement is true about the product square root of 2(3square root of 2 + square root of 14)?

sukhopar [10]

Answer:

$\sqrt{2} (3\sqrt{2} +\sqrt{14})=6+2\sqrt{7}$

Step-by-step explanation:

Given : $\sqrt{2} (3\sqrt{2} +\sqrt{14})$

Solution:

$\sqrt{2} (3\sqrt{2} +\sqrt{14})$

$3*2+\sqrt{28})$

$6+2\sqrt{7}$

Thus , $\sqrt{2} (3\sqrt{2} +\sqrt{14})=6+2\sqrt{7}$

Thus the solution is irrational since square root 7 does not have a perfect square and equal to 6+2square root of 14

3 0

3 years ago

Read 2 more answers

List the ordered pairs in the equivalence relations produced by these partitions of {a, b, c, d, e, f, g}: a) {a,b},{c,d},{e,f,g

finlep [7]

Answer:

a) {a,b} , {c,d} , {e,f,g},{a , b } = {(a,a) (b,b) (a,b) (b,a)},{c , d } = {(c,c) (d,d) (c,d) (d , c) } ,{e,f,g} = {(e,e) (e,f) (f,e) (e,g) (f,f) (f,g) ( g,e) (g,f)(g,g)}

b) { (a,a)(b,b)(c,c)(c,d)(d,c)(d,d)(e,e)(e,f)(f,e)(f,f)(g,g)

c) {(a,a)(a,b)(b,b)(b,a)(a,c)(c,a)(b,c)(c,b)(c,c)(d,a)(a,d)(b,d)(d,b)(d,c)(c,d)(d,d)(c,c)(c,f)(f,c)(f,f)(c,g)(g,c)(f,g)(g,f)(g,g)

Step-by-step explanation:

a) {a,b} , {c,d} , {e,f,g}

{a , b } = {(a,a) (b,b) (a,b) (b,a)}

{c , d } = {(c,c) (d,d) (c,d) (d , c) }

{e,f,g} = {(e,e) (e,f) (f,e) (e,g) (f,f) (f,g) ( g,e) (g,f) (g,g)}

b) {a} ,{b},{c,d} ,{e,f},{g}

{ (a,a)(b,b)(c,c)(c,d)(d,c)(d,d)(e,e)(e,f)(f,e)(f,f)(g,g)}

c) {a,b,c,d},{e,f,g}

{(a,a)(a,b)(b,b)(b,a)(a,c)(c,a)(b,c)(c,b)(c,c)(d,a)(a,d)(b,d)(d,b)(d,c)(c,d)(d,d)(c,c)(c,f)(f,c)(f,f)(c,g)(g,c)(f,g)(g,f)(g,g)

4 0

3 years ago

Find the value of x.

vlada-n [284]

8 / 2 equals to 4

therefore 10 / 2 will be equal to 5

6 0

3 years ago

Solve this problem please

djyliett [7]

The formula for depreciation is:

$y=x(1-r)^t$

Where x = Initial value,

y= Amount after depreciation.

r= Rate of depreciation,

t = time (in years)

According to given problem,

x = 1040, y= 944 and t = 12 months =1 year.

So, first step is to plug in these values in the above formula, So,

$944 = 1040(1-r)^1$

944 = 1040 (1 -r)

$\frac{944}{1040} =1-r$ Divide each sides by 1040.

0.907692308 =1 - r

0.907692308 - 1 = -r Subtract 1 from each sides.

-0.092307692 = -r

So, r = 0.09 or 9%.

Now plug in 0.09 in the above equation to get the depreciation equation. So,

$y = x (1- 0.09)^t$

So, $y = 0.91x^t$

b) To find the value of the bike after 5 months,

plug in t = 5 months= 5/12 = 0.41667 years in the above equation of depreciation.

So, $y= 1040 *(0.91)^{0.41667}$

y = 1040 * 0.961465659

y = 999.9242852

y = 1000 (Rounded to nearest integer).

Hence, the value of the bike after 5 months is $1000.

7 0

3 years ago