Answer:
When the price of a ticket = $0 or $40, there will be no revenue.
The revenue will be $500 if each ticket cost $37.3 or $2.68
Step-by-step explanation:
Let R(p) = p(200-5p)
when R(p) = 0
p(200-5p) = 0
p = 0 or 200-5p = 0
When the price of a ticket = $0 or $40, there will be no revenue.
when R(p) = 500
200p - 5p² = 500
5p² - 200p + 500 = 0
p = $37.3 or $2.68 (3 sig. fig.)
The required prices are $37.3 and $2.68
Answer:
y = -(1/2)x + 2
Step-by-step explanation:
Answer:
Multiply the area of the base by the height and divide by 3.
Step-by-step explanation:
V = (1/3)Bh
where B = area of the base, and
h = height
Answer: Multiply the area of the base by the height and divide by 3.