Answer:
Simplify {4}^{2}42 to 1616.
-16+2\times -4\times -5-2\times {2}^{3}−16+2×−4×−5−2×23
Simplify 2\times -42×−4 to -8−8.
-16-8\times -5-2\times {2}^{3}−16−8×−5−2×23
Simplify 8\times -58×−5 to -40−40.
-16-(-40)-2\times {2}^{3}−16−(−40)−2×23
Use Product Rule: {x}^{a}{x}^{b}={x}^{a+b}xaxb=xa+b.
-16-(-40)-{2}^{4}−16−(−40)−24
Simplify {2}^{4}24 to 1616.
-16-(-40)-16−16−(−40)−16
Remove parentheses.
-16+40-16−16+40−16
Simplify -16+40−16+40 to 2424.
24-1624−16
Simplify.
8
Step-by-step explanation:
hope it helps :)
Answer:
No such a triangle can not exist.
I think it is, (1,1) I think that is it...
Question 1:
Blank 3: ASA congruence (you have two angles and a side)
Blank 4: CPCTC (corresponding parts of congruent triangles are congruent)
Question 2:
Blank 2: Definition of perpendicular lines
Blank 3: Given
Blank 4: SD = SD (Shared side)
Blank 5: HL Theorem (We have two right triangles)
Have an awesome day! :)
The second photo is the correct graph.
