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Lelu [443]
2 years ago
6

The pyramid has a square base and a vertex that lies directly above the center of the square. Which of the following describes h

orizontal cross sections of this solid?
A) They are all squares congruent to the base

B) They are all squares similar to the base

C) They are all triangles similar to the sides

D) They are all triangles congruent to the sides
Mathematics
1 answer:
Step2247 [10]2 years ago
7 0

Answer:

the answer is B

B) They are all squares similar to the base

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A skateboarding ramp is 12 in. high and rises at an angle of 21​°. How long is the base of the​ ramp? Round to the nearest inch.
bagirrra123 [75]

Answer:

the base of the ramp is 31 inches long.

Step-by-step explanation:

c = a/sin(α)

= 33.48514

b = √c2 - a2

= √33.4851373155042 - 122

= √977.25442103816

= 31.26107

3 0
2 years ago
Which is the graph of the linear equality 2x-3y<12
WINSTONCH [101]

Answer:

The graph below shows the answer to

2x - 3y < 12

Also shown as

-3y < -2x + 12

Step-by-step explanation:

You can rearrange the inequality by subtracting 2x from both sides to isolate the y.

You now have -3y < 12 -2x

which can be put into the standard linear equation form of

-3y < -2x + 12

Then you divide both sides by -3 to get singular value of y, which is something like

-3/-3y < -2/-3x + 12/-3

which is

y > 2/3x -4

Note: I switched direction of the inequality because you are dividing both sides by a negative value.

7 0
3 years ago
CAN SOMEONE PLEASE SOLVE THIS PLEASE!!!!!!!!!!!!!!!!!!!!!!!!! NEED HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Yakvenalex [24]

Answer:

Are you cheating?

Step-by-step explanation:

5 0
3 years ago
Write the equation of the line, in slope-intercept form, with the following information: slope: -3/8 point: (16, -1)​
irakobra [83]

Answer:

y+1=-3/8(x-16)

Step-by-step explanation:

I used the equation and plugged in the numbers

y-__y__=__m__(x-__x__)

6 0
3 years ago
Simplify the expression. Write the answer without using parentheses or negative exponents.
rodikova [14]
\frac{ (x^4 y^2)^5 }{ (x^2 y)^2 } =\frac{ x^{4*5} y ^{2*5} }{ x ^{2*2} y ^2 } =\frac{ x^{20} y ^{10} }{ x^4y^2 } = x^{20-4} *y^{10-2}= x^{16} *y^{8}


5 0
3 years ago
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