Answer:
0.5 = 50% probability a value selected at random from this distribution is greater than 23
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the probability a value selected at random from this distribution is greater than 23?
This is 1 subtracted by the pvalue of Z when X = 23. So



has a pvalue of 0.5
0.5 = 50% probability a value selected at random from this distribution is greater than 23
Answer shown and explanation above! Hope this helps!
Correct answer is: P(x<6) is 0.123 and it is usual.
Solution:-
Given that the time a person takes to decide which shoes to purchase follows normal distribution. Which has mean = 8.21 minutes and standard deviation 1.90
Then probability of individual takes less than 6 minutes is
P(X<6) = 
= 
= 0.1230
Typically we say an event with a probability less than 5% is unusual.
But here P(X<6) = 0.123 is greater than 5% hence this is usual.
Find a common multiplier then divide ex. 21/27 = 7/9
Gaga est un ☝ et une bonne nouvelle de mon temps à me dire je me demande pourquoi