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inna [77]
3 years ago
12

What is the equation represented by the order pairs {(0,32),(1,16),(2,8),(3,4)}?

Mathematics
1 answer:
bagirrra123 [75]3 years ago
5 0

Answer:

The equation represented by the ordered pair is;

y = 2^(5-x)

Step-by-step explanation:

Here, we want to write the equation represented by the ordered pairs

From what we have in the question, we can see that while the x-values increase in arithmetic progression of 1

The y-values decrease in order of two geometrically

Thus, the equation is;

y = 2^(5-x)

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Marlow types 90 words in 3 minutes. How many words does he type in 7 hours?<br>​
Contact [7]

Answer:

if I am right it is 12,600 words

Step-by-step explanation: 90 divided by 3 which is 30     420x30=12,600

7 0
3 years ago
Use a calculator or a square root table to approximate to the nearest thousandth
Vadim26 [7]

Answer:

- 13.077

Step-by-step explanation:

Here we have to calculate the square root of a certain number using the help of the calculator or a square root table.

The given expression is - \sqrt{ 171 }.

Now, using calculator \sqrt{ 171 } = 13.076696

Now,  - \sqrt{ 171 } = - 13.076696

So, approximate value to the nearest thousandth is - 13.077 ( Answer )

4 0
2 years ago
NEED HELP FAST!!! Determine the momentum: An electron (m= 9.1 x 10-31 kg) moving at 2.18 x 106 m/s (as if it were in a Bohr orbi
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Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
To obtain information on the corrosion-resistance properties of a certain type of steel conduit, 45 specimens are buried in soil
Fiesta28 [93]

Answer:

The sample has not met the required specification.

Step-by-step explanation:

As the average of the sample suggests that the true average penetration of the sample could be greater than the 50 mils established, we formulate our hypothesis as follow

H_0: The true average penetration is 50 mils

H_a: The true average penetration is > 50 mils

Since we are trying to see if the true average is greater than 50, this is a right-tailed test.

If the <em>level of confidence</em> is α = 0.05 then the z_\alpha score against we are comparing with, is 1.64 (this is because the area under the normal curve N(0;1) to the right of 1.64 is 0.05)

The z-score associated with this test is

z=\frac{\bar x-\mu}{s/\sqrt{n}}

where

\bar x = <em>mean of the sample</em>

\mu = <em>average established by the specification</em>

s = <em>standard deviation of the sample</em>

n = <em>size of the sample</em>

Computing this value of z we get z = 3.42

Since z >z_\alpha we can conclude that the sample has not met the required specification.

5 0
3 years ago
Pleaseee helpppp !!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!
solniwko [45]
ANSWER: FG = 69

FG = FK + KG
KG = 1/2(FK)
FK = 46

RULE: When it comes to centroids, the longer section of the line is always 2/3 of the entire line (+ the shorter section of the line is always 1/3). This means that the shorter section of the line is HALF of the longer section of the line.

FG = FK + KG
FG = 46 + 46/2
FG = 46 + 23
FG = 69

CHECK:
FK = 2/3(FG)
46 = 2*69/3
46 = 138/3
46 = 46 ✔️

or

KG = 1/3(FG)
1/2(FK) = 1/3(FG)
46/2 = 69/3
23 = 23 ✔️
5 0
2 years ago
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