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3 years ago

What is the equation represented by the order pairs {(0,32),(1,16),(2,8),(3,4)}?

Mathematics

1 answer:

bagirrra123 [75]3 years ago

5 0

Answer:

The equation represented by the ordered pair is;

y = 2^(5-x)

Step-by-step explanation:

Here, we want to write the equation represented by the ordered pairs

From what we have in the question, we can see that while the x-values increase in arithmetic progression of 1

The y-values decrease in order of two geometrically

Thus, the equation is;

y = 2^(5-x)

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A convex hexagon has interior angles with measures x^0, (5x - 103); (2x + 60), (7x - 31), (6x -6), and (9x - 100), what is the v

cestrela7 [59]

Answer:

x = 30.66°

Step-by-step explanation:

The sum of the interior angles of a hexagon is 720°

Each angles are x^0, (5x - 103); (2x + 60), (7x - 31), (6x -6), and (9x - 100),

we add all these angles together

x^0 + (5x - 103) + (2x + 60) + (7x - 31) + (6x -6) + (9x - 100) = 720

x^0 = 1

1 + (5x - 103) + (2x + 60) + (7x - 31) + (6x -6) + (9x - 100)

1 + 5x - 103 +2x + 60 + 7x -31 + 6x - 6 + 9x - 100 = 720

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3 years ago

The equation of a circle is given below. x^{2}+(y-2.25)^{2} = \dfrac{196}{169}x 2 +(y−2.25) 2 = 169 196 x, squared, plus, left

Lostsunrise [7]

Center = $(h,k) = (0,2.25)$
Radius = $r = \frac{14}{13}$

Step-by-step explanation:

Here we have following equation : $x^{2}+(y-2.25)^{2} = \dfrac{196}{169}$

We need to find the center & radius of this circle . Let's find out:

We know that , Equation of a circle is given by :

⇒ $(x-h)^2+(y-k)^2=r^2$ ........(1)

Here , (h,k) are the co-ordinates of center & r is the radius of circle.Collectively called as a circle with radius r and center at (h,k) . Let's frame given equation in question :

⇒ $x^{2}+(y-2.25)^{2} = \frac{196}{169}$

⇒ $(x-0)^{2}+(y-2.25)^{2} = (\frac{14}{13})^2$

On comparing this equation with equation (1) we get :

Center = $(h,k) = (0,2.25)$
Radius = $r = \frac{14}{13}$

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