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3 years ago

Pls help find the slope

Mathematics

2 answers:

Setler79 [48]3 years ago

6 0

Answer:

-4 over 5

Step-by-step explanation:

The line goes through the points (-3,1) and (2,-3) which means for every 5 x-values it goes to the right, it goes down 4 values. Meaning -4 over 5

Dafna11 [192]3 years ago

5 0

Answer:

m=-(4)/(5)

Step-by-step explanation:

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nordsb [41]

Answer:

C. 6.736

Step-by-step explanation:

I took the test and got a 100%.

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4 years ago

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miss Akunina [59]

Answer:

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3 years ago

600000+21345???????

Marta_Voda [28]

Answer:

621,345

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3 years ago

A 12 foot ladder is leaning against a building. If the bottom of the ladder is sliding along the pavement directly away from the

ira [324]

Using Pythagoras theorem, the top of the ladder moving down when the foot of the ladder is 3 feet from the wall is of -0.518 feet/sec.

Let distance from the wall to the foot of the ladder is 'x' feet and the height of the top of the ladder is 'y' feet.

Pythagoras theorem, $x^{2} + y^{2} = (12)^{2}$ --->(1)

Given, $\frac{dx}{dt}= 2feet/second$ at x=3

Put x=3 in Pythagoras theorem equation (1)

$(3)^{2} + y^{2} = 144$

$y^{2} = 144 - 9$

$y^{2}$ = 135

y = 11.61

Derive equation (1) w.r.t to 't'

$2x\frac{dx}{dt} + 2y\frac{dy}{dt} = 0$ ---->(2)

substitute the value of 'x', 'dx/dt' and 'y' in equation (2), we get the fast of the top of the ladder moving down when the foot of the ladder is 3 feet from the wall

$2(3)(2) + 2 (11.61)\frac{dy}{dt} = 0$

12 + 23.22 $\frac{dy}{dt}$ = 0

$\frac{dy}{dt}= \frac{-12}{23.22}$

$\frac{dy}{dt} = -0.518$

Hence, using Pythagoras theorem the top of the ladder moving down when the foot of the ladder is 3 feet from the wall is of -0.518 feet/sec.

Learn more about Pythagoras theorem here

brainly.com/question/21511305

#SPJ4

5 0

2 years ago

Choose the answer based on the most efficient method as presented in the lesson.

Grace [21]

Remember that to solve an equation we need to isolate the variable in one side. To do it we can perform any mathematical operations we want as long as we perform the operations to both sides of the equation.

Let's solve our equation step by step

Step 1. Subtract $2x$ from both sides of the equation