Answer:
91.6 km/h
Step-by-step explanation:
Let v = average speed of van = 65 km/h and v' = average speed of car. Let t be the time the car starts to move. The van started 35 minutes earlier at t' = (t + 35/60) h.
Since distance d = vt where v = velocity and t = time, the distance moved by the van d = vt' = v(t + 35/60) and that moved by the car is d' = v't.
Since the car catches up with the van after it had moved a distance of 130 km, d = d' = 130 km.
So d = v(t + 0.583)
Substituting d = 130 km and v = 65 km/h, we have
130 km = 65 km/h(t + 0.583)
130 km = (65t + 37.895 )km
subtracting 37.895 from both sides, we have
130 km - 37.895 km = 65t
92.105 = 65t
dividing both sides by 65, we have
t = 92.105/65
= 1.417 h
≅ 1.42 h
Since d = d' = v't,
v' = d'/t
= 130 km/1.42 h
= 91.55 km/h
≅ 91.6 km/h
So, the average speed of the car is 91.6 km/h
By looking at the graph we can see that f(x) increase by 1 (on the vertical axis . or y-axis ) from 2 to 3, over the interval 0 to 1 ( horizontal axis, or x-axis)
It increases by 2 over the interval 1 to 2.
by 4 over the interval 2 to 3.
And by 8 over the interval 3 to 4.
Therefore this exponential function grows by a factor of 2 (since it doubles every by every interval of 1)
Answer:
84
Step-by-step explanation:
Pretend her first 3 quizzes were all 83 since that was the average. So the 4th was 87.
83+83+83+87 = 336
Divide by the total number of quizzes because they are equally weighted.
336/4 = 84
Her new average score is 84.
Step-by-step explanation:
If your question is x² + 5xy
Then,
Numerical coefficient = Number in the given expression
Numerical coefficient = 5
Option A
