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tatuchka [14]
2 years ago
11

There are 63 marbles in a leather bag. Some of the marbles are blue, some are green, some are clear, some are gold, and some are

red. Based on experimental probability, there is a 1 in 7 chance of pulling out a blue marble. About how many blue marbles might be in the entire bag?
Group of answer choices

7 blue marbles

13 blue marbles

9 blue marbles

6 blue marbles
Mathematics
1 answer:
sveticcg [70]2 years ago
4 0

Answer:9

Step-by-step explanation:1/7 of 63 =9

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|-6+8| = simplify the expression
lilavasa [31]

Answer:

2

Step-by-step explanation:

|-6+8|

Add/subtract the numbers: -6 + 8 = 2

= |2|

Apply the absolute value rule: |a| = a, a ≥ 0

= 2

8 0
3 years ago
Please help me and explain this.
Zina [86]
You are supposed to answer where the function, h(x), is decreasing. In other words, where is “y” decreasing.

In this graph, I believe it would be from (-3,4)U(8,infinity). I hope this helps.
8 0
3 years ago
How to find slope y=3x+5
klemol [59]

This equation is in slope-intercept form; y = mx+b.

m is the slope and b is the y-intercept, so to find the slope you'd look at the coefficient of x.

In this equation, y = 3x+5, the coefficient of x is 3, so that means that the slope of this equation is 3.

Answer is:

3 is the slope

3 0
3 years ago
A cone has a diameter of 24cm and a volume of 2713cm3. What is best approximation of height of cone?
Leokris [45]
V=(1/3)hpir^2
aprox

d=2r
d/2=r
d=24
r=24/2=12

V=2713

2713=(1/3)hpi(12^2)
2713=(1/3)hpi(144)
2713=48pih
divide both sides by 48
56.5208=hpi
aprox pi=3.14
divide both sides by 3.14
56.5208/3.14=h=18.0003
height=18cm
7 0
3 years ago
Helppppppppp pleaseeee Someoneeeee pleaseeee I neeed
Stella [2.4K]

Answer:

The minimum value of f(x) is 2

Step-by-step explanation:

  • To find the minimum value of the function f(x), you should find the value of x which has the minimum value of y, so we will use the differentiation to find it
  • Differentiate f(x) with respect to x and equate it by 0 to find x, then substitute the value of x in f(x) to find the minimum value of f(x)

∵ f(x) = 2x² - 4x + 4

→ Find f'(x)

∵ f'(x) = 2(2)x^{2-1} - 4(1)x^{1-1} + 0

∴ f'(x) = 4x - 4

→ Equate f'(x) by 0

∵ f'(x) = 0

∴ 4x - 4 = 0

→ Add 4 to both sides

∵ 4x - 4 + 4 = 0 + 4

∴ 4x = 4

→ Divide both sides by 4

∴ x = 1

→ The minimum value is f(1)

∵ f(1) = 2(1)² - 4(1) + 4

∴ f(1) = 2 - 4 + 4

∴ f(1) = 2

∴ The minimum value of f(x) is 2

7 0
3 years ago
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