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3 years ago

3. Numerical coefficient of x² in= x++5xy is a) 5 b) - 5/2 c) 5/2 d) 1/2

Mathematics

2 answers:

arlik [135]3 years ago

6 0

Step-by-step explanation:

If your question is x² + 5xy

Then,

Numerical coefficient = Number in the given expression

Numerical coefficient = 5

Option A

nlexa [21]3 years ago

5 0

Step-by-step explanation:

Solution,

In x+5xy

The numerical coefficient is 5.

Hence, option a is correct.

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Solve the equation sin x + cos x=cos 2x for 0 27. x

vodka [1.7K]

Answer:

$x=\frac{\pi}{4}$ and $x=-\frac{3\pi}{4}$

Step-by-step explanation:

We are given that sin x+cos x=cos 2x

We have to solve the given equation for $0\leq x\leq 2\pi$

$sin x+cos x=cos^2x-sin^2x$

Because $cos 2x=cos^2-sin^2$

$sinx+cos x=(sinx +cos x)(sinx-cos x)$

$1 =sin x-cos x$

$sin x=cos x$

$\frac{sinx }{cos x}=1$

$tan x=1$

$tan x=\frac{sinx}{cos x}$

$tan x=tan\frac{\pi}{4}$

$x=\frac{\pi}{4}$

Tan x is positive in I and III quadrant

In III quadrant angle $\theta$ replace by $\theta -\pi$

Therefore, $tan x=tan (\frac{\pi}{4}-\pi)=tan\frac{\pi-4\pi}{4}=tan\frac{-3\pi}{4}$

$x=-\frac{3\pi}{4}$

8 0

2 years ago

Convert: 6y + y² = x² from rectangular to polar form.

11Alexandr11 [23.1K]

$\bf \textit{Double Angle Identities}
\\ \quad \\
sin(2\theta)=2sin(\theta)cos(\theta)
\\ \quad \\\\
cos(2\theta)=
\begin{cases}
\boxed{cos^2(\theta)-sin^2(\theta)}\\
1-2sin^2(\theta)\\
2cos^2(\theta)-1
\end{cases}\\\\\\
tan(2\theta)=\cfrac{2tan(\theta)}{1-tan^2(\theta)}\\\\
-------------------------------\\\\$

$\bf 6y+y^2=x^2\implies \cfrac{6y}{x^2}+\cfrac{y^2}{x^2}=1\implies \cfrac{6rsin(\theta )}{[rcos(\theta )]^2}+\cfrac{[rsin(\theta )]^2}{[rcos(\theta )]^2}=1
\\\\\\
\cfrac{6rsin(\theta )}{r^2cos^2(\theta )}+\cfrac{r^2sin^2(\theta )}{r^2cos^2(\theta )}=1\implies 
\cfrac{6sin(\theta )}{rcos^2(\theta )}+\cfrac{sin^2(\theta )}{cos^2(\theta )}=1$

$\bf \cfrac{6sin(\theta )}{rcos^2(\theta )}=1-\cfrac{sin^2(\theta )}{cos^2(\theta )}\implies \cfrac{6sin(\theta )}{1-\frac{sin^2(\theta )}{cos^2(\theta )}}=rcos^2(\theta )
\\\\\\
\cfrac{6sin(\theta )}{cos^2(\theta )\left[ 1-\frac{sin^2(\theta )}{cos^2(\theta )} \right]}=r\implies \cfrac{6sin(\theta )}{cos^2(\theta )-sin^2(\theta )}=r
\\\\\\
\cfrac{6sin(\theta )}{cos(2\theta )}=r$

5 0

3 years ago

What is 36 divided by 540 using partial quosient

iogann1982 [59]

excuse the writing io used my mouse
so the aim is to find a simple factor thst when u multiply the divisoor by it si lower thatn the dividend
in this case i used 10 so 10*36=360
then u subtract 360 ( 540-360=180)from the dividend and record the ten which i did on right side of the attachment
then u find another factor that can now multiply 36 but be less that 180 i chose 5
5*36=180
180-180= 0
finally u jus add the factors that used which are the 10 and 5= 15
therefore 540/36 =15

6 0

3 years ago

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The average body temperature of a lemming is 98.6 degrees Fahrenheit. The

rosijanka [135]

I’m doing this too hopefully someone answers quick cause I’m confused also.

6 0

3 years ago

What is the simplest form of √126xy^5/32x^3 (square root of the entire thing btw)

grandymaker [24]

Answer:

Step-by-step explanation: