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Alexxx [7]
3 years ago
8

To celebrate 24 years in business, a clothing store's marketing executive is ordering scratch-off discount coupons to give to cu

stomers. She would like 40% of customers in the population to receive the highest possible discount, with an SEP of 0.01 for this population. How many coupons should she order?
Mathematics
1 answer:
Rina8888 [55]3 years ago
8 0

Answer:

She should order 2400 coupons.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

She would like 40% of customers in the population to receive the highest possible discount, with an SEP of 0.01 for this population.

This means that p = 0.4, s = 0.01

How many coupons should she order?

We have to find n. So

s = \sqrt{\frac{p(1-p)}{n}}

0.01 = \sqrt{\frac{0.4*0.6}{n}}

0.01\sqrt{n} = \sqrt{0.4*0.6}

\sqrt{n} = \frac{\sqrt{0.4*0.6}}{0.01}

(\sqrt{n})^2 = (\frac{\sqrt{0.4*0.6}}{0.01})^2

n = 2400

She should order 2400 coupons.

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Several terms of a sequence {an}n=1 infinity are given. A. Find the next two terms of the sequence. B. Find a recurrence relatio
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Answer:

A)\frac{1}{1024},\frac{1}{4096}

B) \left\{\begin{matrix}a(1)=1 & \\ a(n)=a(n-1)*\frac{1}{4} &\:for\:n=1,2,3,4,... \end{matrix}\right.

C) \\a_{n}=nq^{n-1} \:for\:n=1,2,3,4,...

Step-by-step explanation:

1) Incomplete question. So completing the several terms:\left \{a_{n}\right \}_{n=1}^{\infty}=\left \{ 1,\frac{1}{4},\frac{1}{16},\frac{1}{64},\frac{1}{256},... \right \}

We can realize this a Geometric sequence, with the ratio equal to:

q=\frac{1}{4}

A) To find the next two terms of this sequence, simply follow multiplying the 5th term by the ratio (q):

\frac{1}{256}*\mathbf{\frac{1}{4}}=\frac{1}{1024}\\\\\frac{1}{1024}*\mathbf{\frac{1}{4}}=\frac{1}{4096}\\\\\left \{ 1,\frac{1}{4},\frac{1}{16},\frac{1}{64},\frac{1}{256},\mathbf{\frac{1}{1024},\frac{1}{4096}}\right \}

B) To find a recurrence a relation, is to write it a function based on the last value. So that, the function relates to the last value.

\left\{\begin{matrix}a(1)=1 & \\ a(n)=a(n-1)*\frac{1}{4} &\:for\:n=1,2,3,4,... \end{matrix}\right.

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\\a_{n}=nq^{n-1} \:for\:n=1,2,3,4,...

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Step-by-step explanation:

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Area =L×W

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