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3 years ago

Please help me out I really can’t afford failing this test

Mathematics

1 answer:

Blizzard [7]3 years ago

7 0

Answer:

I'm not really sure but I think it's 2

Step-by-step explanation:

So here's what I did;

x³+3x-9=x - 1 +2x

x³+3x - x -2x = 9 - 1

x³= 8

x = ³√8

x = 2

I hope this helps

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What is the range of 1/2 1/8 1/2 5/8 1/4 1/4 1/2 3/4 1/8 5/8 1/4 1/2

LenaWriter [7]

Answer:

it is 1/8- 5/8 smallest to biggesst

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3 years ago

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What are the solutions of -1 ≤ x – 3 < 4

cricket20 [7]

Answer:

2 ≤ x < 7

Step-by-step explanation:

-1 ≤ x – 3 < 4

Add 3 to each side

-1+3 ≤ x – 3+3 < 4+3

2 ≤ x < 7

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3 years ago

Solve the system of equations

nekit [7.7K]

Answer: x = 3 and y = 1

Step-by-step explanation:

y = - x + 4 ............... equation 1

y = x - 2 ............. equation 2

Solving the linear equation by substitution method , we have :

substitute equation 2 into equation 1 , that is

x - 2 = - x + 4

Add 2 to both sides , we have

x = -x + 4 + 2

Add x to both sides , we have

2x = 6

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Therefore : x = 3 and y = 1

8 0

3 years ago

15 points to answer this question

Mamont248 [21]

it is none since there is no relation

4 0

4 years ago

Read 2 more answers

Psychologist Michael Cunningham conducted a survey of university women to see whether, upon graduation, they would prefer to mar

bagirrra123 [75]

Answer:

A.The probability that exactly six of Nate's dates are women who prefer surgeons is 0.183.

B. The probability that at least 10 of Nate's dates are women who prefer surgeons is 0.0713.

C. The expected value of X is 6.75, and the standard deviation of X is 2.17.

Step-by-step explanation:

The appropiate distribution to us in this model is the binomial distribution, as there is a sample size of n=25 "trials" with probability p=0.25 of success.

With these parameters, the probability that exactly k dates are women who prefer surgeons can be calculated as:

$P(x=k) = \dbinom{n}{k} p^{k}(1-p)^{n-k}\\\\\\P(x=k) = \dbinom{25}{k} 0.25^{k} 0.75^{25-k}\\\\\\$

A. P(x=6)

$P(x=6) = \dbinom{25}{6} p^{6}(1-p)^{19}=177100*0.00024*0.00423=0.183\\\\\\$

B. P(x≥10)

$P(x\geq10)=1-P(x$

$P(x=0) = \dbinom{25}{0} p^{0}(1-p)^{25}=1*1*0.0008=0.0008\\\\\\P(x=1) = \dbinom{25}{1} p^{1}(1-p)^{24}=25*0.25*0.001=0.0063\\\\\\P(x=2) = \dbinom{25}{2} p^{2}(1-p)^{23}=300*0.0625*0.0013=0.0251\\\\\\P(x=3) = \dbinom{25}{3} p^{3}(1-p)^{22}=2300*0.0156*0.0018=0.0641\\\\\\P(x=4) = \dbinom{25}{4} p^{4}(1-p)^{21}=12650*0.0039*0.0024=0.1175\\\\\\P(x=5) = \dbinom{25}{5} p^{5}(1-p)^{20}=53130*0.001*0.0032=0.1645\\\\\\P(x=6) = \dbinom{25}{6} p^{6}(1-p)^{19}=177100*0.0002*0.0042=0.1828\\\\\\$

$P(x=7) = \dbinom{25}{7} p^{7}(1-p)^{18}=480700*0.000061*0.005638=0.1654\\\\\\P(x=8) = \dbinom{25}{8} p^{8}(1-p)^{17}=1081575*0.000015*0.007517=0.1241\\\\\\P(x=9) = \dbinom{25}{9} p^{9}(1-p)^{16}=2042975*0.000004*0.010023=0.0781\\\\\\$

$P(x\geq10)=1-(0.0008+0.0063+0.0251+0.0641+0.1175+0.1645+0.1828+0.1654+0.1241+0.0781)\\\\P(x\geq10)=1-0.9287=0.0713$

C. The expected value (mean) and standard deviation of this binomial distribution can be calculated as:

$E(x)=\mu=n\cdot p=25\cdot 0.25=6.25\\\\\sigma=\sqrt{np(1-p)}=\sqrt{25\cdot 0.25\cdot 0.75}=\sqrt{4.69}\approx2.17$

4 0

3 years ago