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hjlf
3 years ago
5

Write an ordered pair to represent the reflection of the point (4,-1) in the x axis

Mathematics
2 answers:
defon3 years ago
8 0

Answer:

(4,1)

Step-by-step explanation:

The rule for reflecting over the X axis is to switch the value of the y-coordinate of each point, but leave the x-value the same

vodomira [7]3 years ago
3 0
Point should be (4,1) if being reflected across the x axis
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All the dimensions of a triangle were multiplied by the same factor. If the base of the triangle went from 1 centimeter to 3 cen
timama [110]
The answer is 9.

To calculate this, we will use Galileo's square cube law, used to describe the change of the area or the volume of the shape, when their dimensions increase or decrease. The formula used for change of the area is
A_2= A_1 (\frac{l_2}{l_1} )^{2}
A₂ - the area after the change,
A₁ - the area before the change,
l₂ - the dimension after the change,
l₁ - the dimension before the change.


It is given:
l₁ = 1 cm
l₂ = 3 cm

Let's use this formula for the mentioned triangle:
A_2=A_1( \frac{l_2}{l_1}) ^{2}  =A_1( \frac{3}{1})^{2} =A_1*3 ^{2} =9A_1

Therefore, the area of the triangle was multiplied by 9.
8 0
3 years ago
Express the limit as a definite integral on the given interval. lim n→[infinity] n xi ln(1 + xi2) Δx, [2, 7] i = 1
xenn [34]

Answer:

Step-by-step explanation:

Consider \  the \ following \ series

\lim_{n \to \infty}  \sum \limits ^n_{i=1} x_i \ In ( 1+ x_i^2) \Delta x , [2,7]

Let's \ recall \ the \ explanation \  of definite \ integral \ in  \ terms  \ of  \ Riemann \ sum

\int^b_a \ f(x) \ dx =  \lim_{n \to \infty}  \sum \limits ^n_{i=1} \ f(x_i) \Delta x , \ where \ \Delta x = \dfrac{b-a}{n}

By  \ efinition,  \ the \  limit \   is \  then \  expressed \   as  \  integral

\lim_{n \to \infty} \sum ^a_{i=1} \ x_i \ In (1+x_i^2) \Delta x = \int^7_2 xIn (1+x^2) \ dx

7 0
2 years ago
Drag the tiles to the correct boxes to complete the pairs.
Len [333]

<u>Answer:</u>

1. (-2^2)^{-6} ÷ (2^{-5})^{-4} \implies 2^{-32}

2. 2^4 . (2^2)^{-2} \implies 1

3. (-2^{-4}).(2^2)^0 \implies -2^8

4. (2^2).(2^3)^{-3} \implies 2^{-5}

<u>Step-by-step explanation:</u>

1. (-2^2)^{-6} ÷ (2^{-5})^{-4} :

= \frac{ ( - 2 ^ 2 ) ^ { - 6 } } { ( 2 ^ { - 5 } ) ^ { - 4 } } = \frac{2^{-12}}{2^{20}} = 2^{-12-20}=2^{-32}

2. 2 ^ 4 . ( 2 ^ 2 ) ^ { - 2 } :

= 2^4 \times \frac{1}{2^4} = 1

3. (-2^{-4}).(2^2)^0 :

= (-2^4)^2 \times 1 = -2^8

4. (2^2).(2^3)^{-3} :

= 2^4 \times \frac{1}{2^9} =\frac{1}{2^5} =2^{-5}

5 0
3 years ago
Read 2 more answers
Determine the sum: 21.6 x 10^4 + 5.2 x 10^7. Write your answer in scientific notation.
lana [24]

Answer:

It's D

Step-by-step explanation:

Hope this helps :))

6 0
2 years ago
Does the relationship in this table represent a proportional relationship?
const2013 [10]

Answer:

They are un-proportional.

Step-by-step explanation:

The ratios dont have the same relationship.

6 0
2 years ago
Read 2 more answers
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