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3 years ago

H(x)=2x-6 find the value. -2[h(3)]

Mathematics

1 answer:

defon3 years ago

3 0

Answer:

-2[h(3)] = 0

Step-by-step explanation:

Step 1: Define

h(x) = 2x - 6

Step 2: Find h(3)

h(3) = 2(3) - 6

h(3) = 6 - 6

h(3) = 0

Step 3: Find -2[h(3)]

-2(0)

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Simplify (5 + 1)2 - (11 + 32) + 4.

4vir4ik [10]

Answer:

Step-by-step explanation:

The trick here is to know PEMDAS.

PEMDAS stands for: Parentheses, Exponents, Multiplication, Division, Addition, Subtraction.

This is the order in which you should simplify a problem.

Parentheses:

(5 + 1)^2 - (11 + 32) + 4

(6)^2 - (43) + 4

Exponents:

(6)^2 - (43) + 4

36 - 34 + 4

We have no multiplication or division, so we can skip those steps.

Addition:

36 - 34 + 4

40 - 34

Subtraction:

40 - 34

So 6 is our answer.

5 0

3 years ago

Read 2 more answers

Please help me. This is real confusing.

katrin2010 [14]

Answer:

1st problem: b) $A=2500(1.01)^{12t}$

2nd problem: c) $A=2500e^{.12t}$

Step-by-step explanation:

1st problem:

The formula/equation you want to use is:

$A=P(1+\frac{r}{n})^{nt}$

where

t=number of years

A=amount he will owe in t years

P=principal (initial amount)

r=rate

n=number of times the interest is compounded per year t.

We are given:

P=2500

r=12%=.12

n=12 (since there are 12 months in a year and the interest is being compounded per month)

$A=2500(1+\frac{.12}{12})^{12t}$

Time to clean up the inside of the ( ).

$A=2500(1+.01)^{12t}$

$A=2500(1.01)^{12t}$

----------------------------------------------------

2nd Problem:

Compounded continuously problems use base as e.

$A=Pe^{rt}$

P is still the principal

r is still the rate

t is still the number of years

A is still the amount.

You are given:

P=2500

r=12%=.12

Let's plug that information in:

$A=2500e^{.12t}$ .

6 0

3 years ago

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Consider the functions given below. SEE F

Wewaii [24]

Answer:

1. $P(x)$ ÷ $Q(x)$ ---> $\frac{-3x + 2}{3(3x - 1)}$

2. $P(x) + Q(x)$ ---> $\frac{2(6x - 1)}{(3x - 1)(-3x + 2)}$

3. $P(x) - Q(x)$ ---> $\frac{-2(12x - 5)}{(3x - 1)(-3x + 2)}$

4. $P(x)*Q(x)$ --> $\frac{12}{(3x - 1)(-3x + 2)}$

Step-by-step explanation:

Given that:

1. $P(x) = \frac{2}{3x - 1}$

$Q(x) = \frac{6}{-3x + 2}$

Thus,

$P(x)$ ÷ $Q(x)$ = $\frac{2}{3x - 1}$ ÷ $\frac{6}{-3x + 2}$

Flip the 2nd function, Q(x), upside down to change the process to multiplication.

$\frac{2}{3x - 1}*\frac{-3x + 2}{6}$

$\frac{2(-3x + 2)}{6(3x - 1)}$

$= \frac{-3x + 2}{3(3x - 1)}$

2. $P(x) + Q(x)$ = $\frac{2}{3x - 1} + \frac{6}{-3x + 2}$

Make both expressions as a single fraction by finding, the common denominator, divide the common denominator by each denominator, and then multiply by the numerator. You'd have the following below:

$\frac{2(-3x + 2) + 6(3x - 1)}{(3x - 1)(-3x + 2)}$

$\frac{-6x + 4 + 18x - 6}{(3x - 1)(-3x + 2)}$

$\frac{-6x + 18x + 4 - 6}{(3x - 1)(-3x + 2)}$

$\frac{12x - 2}{(3x - 1)(-3x + 2)}$

$= \frac{2(6x - 1}{(3x - 1)(-3x + 2)}$

3. $P(x) - Q(x)$ = $\frac{2}{3x - 1} - \frac{6}{-3x + 2}$

$\frac{2(-3x + 2) - 6(3x - 1)}{(3x - 1)(-3x + 2)}$

$\frac{-6x + 4 - 18x + 6}{(3x - 1)(-3x + 2)}$

$\frac{-6x - 18x + 4 + 6}{(3x - 1)(-3x + 2)}$

$\frac{-24x + 10}{(3x - 1)(-3x + 2)}$

$= \frac{-2(12x - 5}{(3x - 1)(-3x + 2)}$

4. $P(x)*Q(x) = \frac{2}{3x - 1}* \frac{6}{-3x + 2}$

$P(x)*Q(x) = \frac{2*6}{(3x - 1)(-3x + 2)}$

$P(x)*Q(x) = \frac{12}{(3x - 1)(-3x + 2)}$

4 0

3 years ago

In a triangle, the sum of the measures of the first two angles is 12 less than the measure of the third angle. In addition, the

USPshnik [31]

The measure of the three angles are 56, 28 , 192 degree

<h3>What is a Triangle ?</h3>

A triangle is a polygon with three sides , three vertices an three angles.

It is given to make system of equations

Let the measure of the first , second and third angle be x, y and z

the sum of the measures of the first two angles is 12 less than the measure of the third angle.

x +y = z -12 ----1

the measure of the first angle is twice as big as the measure of the second angle.

x = 2y

Now equation 1 will be

z - 3y = 12

x +y+z = 180

2y +y +z = 180

3y +z = 180 ----2

z - 3y = 12------3

On solving the system of equation 1, 2

2z = 192

z= 96 degree

3y = 180-96

y = 28

x = 56

Therefore the measure of the three angles area 56, 28 , 192 degree.

To know more about Triangle

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8 0

2 years ago

Evaluate the following numerical expressions. 6 + 23 • 3 =

klasskru [66]

6 + 23(3)

6 + 69

Hope this helps! ;)

3 0

3 years ago

Read 2 more answers