Y = 3x + 4
y = -x - 4
3x + 4 = -x - 4
3x + x = -4 - 4
4x = -8
x = -8/4
x = -2
y = 3x + 4
y = 3(-2) + 4
y = -6 + 4
y = -2
solution is (-2,-2) <==
5 and 1/4 can be cut from the ribbon
Divide 3 1/2 and 2/3
A square pyramid is a pyramid with a square base. In this problem, this base is formed by the points B, C, D and E as illustrated in the Figure above. So, the correct answers are:
First. (BC←→ and DE←→)
This is indicated in Figure 1. As you can see, the red lines are parallel, that is:
![\overline{BC} \ is \ parallel \ to \ \overline{DE}](https://tex.z-dn.net/?f=%5Coverline%7BBC%7D%20%5C%20is%20%5C%20parallel%20%5C%20to%20%5C%20%5Coverline%7BDE%7D)
Recall that two lines are parallel if they are always the same distant apart in which case they are <em>equidistant, </em>that is, they never meet.
Second. (CD←→ and BE←→)
This is indicated in Figure 2. As you can see, the green lines are parallel, that is:
![\overline{CD} \ is \ parallel \ to \ \overline{BE}](https://tex.z-dn.net/?f=%5Coverline%7BCD%7D%20%5C%20is%20%5C%20parallel%20%5C%20to%20%5C%20%5Coverline%7BBE%7D)
<span>If s(x) = 2 – x^2 and t(x) = 3x
s(t) = 2-(3x)^2
(st)(-7)= 2-(3(-7))^2
</span><span>(st)(-7)=2-(-21)^2
</span><span>(st)(-7)=2-(441)
</span><span>(st)(-7)= - 439.
</span>
thus the right option is -439