I WILL MARK BRAINLIEST NEED ASAP PLS

Solve the system using linear combinations.<br> –5x + y = 1<br> 9x – 2y = 4

larisa [96]

Multiply first equation with 2. Then add first and second, we get -x=6. X=-6 and y=-29

8 0

3 years ago

Read 2 more answers

Which graph represents the function y = 2/3x-2

Alina [70]

Answer:

C

Step-by-step explanation:

so the y-int is where the point is on the y-axis (0,X). Or, in this situation-2.

for slope, you just need to do rise over run, or up and down first then, left and right. If I do that for C, I go 2 up and 3 right. So the slope os 2/3 (P.S. up and right is positive, and down and left is negative)

7 0

3 years ago

Find the average rate of change of k(x)=5x–19 over the interval [<br> -<br> 14,<br> -<br> 4].

rusak2 [61]

The rate of change of a function can be modeled with the following expression:

$\frac{\Delta{k{x)}}{\Delta{x}}$

Where Δx is the change in x value, and Δk(x) is the corresponding change in k(x). We're given the two extremes of x, so we can calculate the change in x to be

$\Delta{x}=-4-(-14)=10$

To find the change in k(x), we can calculate the values of k(x) at x = -14 and x = -4 and find the difference between them:

$k(-14)=5(-14)-19=-70-19=-89\\ k(-4)=5(-4)-19=-20-19=-39\\ \Delta{y}=k(-14)-k(-4)=-89-(-39)=-50$

So, the rate of change for the function from x = -14 to x = -4 is

$\frac{\Delta{y}}{\Delta{x}}= \frac{-50}{10}=-5$

7 0

4 years ago

Pls solve part b) iii thanks

Viktor [21]

The bearing of the tree from Q is 296.565°

<h3>How to determine the height of the tree?</h3>

The figure that illustrates the bearing and the distance is added as an attachment

The given parameters are:

Base of the tree, b = 50 meters

Angle (x) = 32 degrees

Calculate the height (h) of the tree using:

tan(x) = height/base

So, we have:

tan(32°) = h/50

Make h the subject

h= 50 × tan(32°)

Evaluate

h = 31.24

Hence, the height of the tree is 31.24 meters

<h3>How to determine the distance between Q and the base of the tree?</h3>

The distance (d) between Q and the base of the tree

This is calculated using the following Pythagoras theorem

d = √(100² + 50²)

Evaluate

d = 111.80

Hence, the distance between Q and the base of the tree is 111.80 meters

<h3>How to determine the angle of elevation?</h3>

The angle of elevation (x) using the following tangent trigonometric ratio

tan(x) = h/d

This gives

tan(x) = 31.24/111.80

Evaluate the quotient

tan(x) = 0.2794

Take the arc tan of both sides

x = 15.61

<h3>The bearing of the tree from Q </h3>

This is calculated using:

Angle of bearing = 270 + arctan(50/100)

Evaluate the arc tan

Angle of bearing = 270 + 26.565

Evaluate the sum

Angle of bearing = 296.565

Hence, the bearing of the tree from Q is 296.565 degrees