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pogonyaev
3 years ago
6

60 x 5=? show me something cute EX

Mathematics
2 answers:
Evgesh-ka [11]3 years ago
6 0

Answer:

60×5= 0×5= 0= 6×5= 30

= 300

andre [41]3 years ago
3 0

Answer:

60 x 5 = 300

and here's something cute

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Simplify the expression: 6 + 3(x + 4) A 6 + 3x + 12 B 9x + 36 C 3x + 18 D 9x + 4
zepelin [54]

Answer:

C

Step-by-step explanation:

6 + 3(x + 4)

= 6 + 3x + 12

= 3x + 18

5 0
3 years ago
Question: A square with sides of length 5 is positioned inside a square with sides of length 7. What is the total area between t
Sergio [31]

Answer:

The total area between the squares is of 24 units squared.

Step-by-step explanation:

Area of a square:

The area of a square of side length l is given by:

A = l^2

Area between figures:

The area between two figures is the area of the larger figure subtracted by the area of the smaller figure.

Larger square:

Square with side of length 7. So

A_l = 7^2 = 49

Smaller square:

Square with side of length 5. So

A_s = 5^2 = 25

What is the total area between the squares? ​

T = A_l - A_s = 49 - 25 = 24

The total area between the squares is of 24 units squared.

6 0
3 years ago
Help please!!!! Best answers!!
Snezhnost [94]
A Probability near 1 Indicates an Unlikely Event . I'm Guessing
8 0
3 years ago
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What are the steps you would take to find the area of
kodGreya [7K]

Answer: Identify the shapes you will need to determine the area of the figure.

Calculate and add the areas of the unshaded triangle and two circles.

Step-by-step explanation:

3 0
3 years ago
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What is the range of the function f(x) = 3x2 + 6x – 8?
timama [110]

Answer:

Range is {y | y ≥ –11}


Step-by-step explanation:

This is quadratic equation.

<em>A quadratic equation's range can be found if we find the vertex.</em>

For quadratic equations that have a positive number in front of  x^{2} , it is upward opening and thus <u>all the numbers greater than or equal to the minimum value of vertex is the range.</u>


The formula for vertex of a parabola is:

Vertex =  (-\frac{b}{2a}, f(-\frac{b}{2a})

Where,

  • a is the coefficient of x^{2}
  • b is the coefficient of x

From our equation given, a=3  and  b=6

Now, x coordinate of vertex is  x=-\frac{b}{2a}\\x=-\frac{6}{(2)(3)}\\x=-\frac{6}{6}\\x=-1

y coordinate of the vertex IS THE MINIMUM VALUE that we want. We get this by plugging in the x value [ x=-1 ] into the equation. So we have:

3(-1)^{2}+6(-1)-8\\=-11


Hence, the range would be all numbers greater than or equal to -11  

Third answer choice is the right one.


6 0
3 years ago
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