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seraphim [82]
2 years ago
5

The number of girls (G) taking French at Mesa High School is 3 more than twice the number of boys (B). A total of 141 students a

re enrolled in French class. What is a system of equations that can be used to find the number of boys taking French and the number of girls taking French?
A) G+2B=3 B+G=141
B) G-2B=3 B+G=141
C) B +3=26 B+G= 141
D) B=2G+3 B + G = 141
Mathematics
2 answers:
Leya [2.2K]2 years ago
7 0
Answer: B - G-2B=3 B+G=141
iris [78.8K]2 years ago
5 0
B) G-2B=3 B+G=141 hopefully it’s right
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A company manufactures and sells x television sets per month. The monthly cost and price-demand equations are
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A) The maximum revenue is 450000$

B) The maximum profit is 216000$ when 2400 sets are manufactured and sold for 180$ each

C) When each set is taxed at ​$55​, the maximum profit is 99125$ when 1850 sets are manufactured and sold for 207.5$ each.

A)p(x)=300−(x/20​),

revenue R(x)=p*x

revenue R(x)=300x -(x2/20)

for maximum revenue dR/dx =0 ,

=>300-(2x/20)=0

=>x/10=300

=>x=3000

maximum revenue = R(3000)=300*3000 -(30002/20)

maximum revenue = R(3000)=450000$

B) profit =revenue -cost

profit P(x)=300x -(x2/20)-72000-60x

profit P(x)=240x -(x2/20)-72000

for maximum cost dP/dx =0

240 -(2x/20)=0

x=240*10

x=2400

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profit P(2400)=240*2400 -(24002/20)-72000 =216000

The maximum profit is 216000$ when 2400 sets are manufactured and sold for 180$ each

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profit =revenue -cost -tax

profit P(x)=300x -(x2/20)-72000-60x-55x

profit P(x)=185x -(x2/20)-72000

for maximum cost dP/dx =0

185-(2x/20)=0

x=185*10

x=1850

p(1850)=300−(1850/20​)=207.5

profit P(1850)=185*1850 -(18502/20)-72000

profit P(1850)=99125$

When each set is taxed at ​$55​, the maximum profit is 99125$ when 1850 sets are manufactured and sold for 207.5$ each.

To know more about maximum profit check the below link:

brainly.com/question/4166660

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