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3 years ago

What is 6,384 times 745

Mathematics

1 answer:

fgiga [73]3 years ago

5 0

Answer:

4756080

Step-by-step explanation:

I hope this helps you

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When planting a garden, 17 out of 25 plants sprout on time.

iogann1982 [59]

Answer:

8/25 or 32%

Step-by-step explanation:

if 17/25 do sprout on time than 8 or the twenty five don't. So 8/25 is the amount that don't and by multiplying both the top and bottom fraction by 4 you will get 32/100 or 32%

4 0

3 years ago

Anyone got an answer?

Furkat [3]

Answer: I am learning this right now, and the right answer is c

Step-by-step explanation: If you set it up correctly it is going to be a fraction, and d cannot be solved so that leaves you with c.

7 0

3 years ago

Read 2 more answers

Find the value of x. m∠IHG = 162° m∠IHK = (4x + 4)° m∠KHG = (8x + 2)°

kirill [66]

Answer:

Step-by-step explanation:

<IHG = 162

<IHK = 4x + 4

<KHG = 8x + 2

<IHG + <IHK + <KHG = 180° (sum of angles in a triangle is equal to 180°)

See attachment for better illustration of the triangle

162 + (4x + 4) + (8x + 2) = 180

162 + 4x + 4 + 8x + 2 = 180

168 + 12x = 180

Collect liketerms

12x = 180 - 168

12x = 12

x = 1

7 0

4 years ago

Read 2 more answers

Can you please do 1 to 10

ehidna [41]

1) 4(x-6)<2
2) 7n+19<8
3) 3(11+x)>=15
4) 4n-12<6
5) 2n+14>=1
6) 2(x+7)>=10
7) 11n-3>9
8)8x+4<=13
9)5n+16>=9
10) 4(x+2)<14

3 0

4 years ago

A printer has a contract to print 100,000 posters for a political candidate. He can run the posters by using any number of plate

yulyashka [42]

Answer:

Step-by-step explanation:

From the given information;

Numbers of posters that can be printed in an hour = no of impression/hour × no of plate utilized in each impression.

= 1000x

Thus, the required number of hours it will take can be computed as:

$\implies \dfrac{100000}{1000x} \\ \\ =\dfrac{100}{x}$

cost per hour = 125

If each plate costs $20 to make, then the total number of plate will equal to 40x

∴

The total cost can be computed as:

$C(x) = (\dfrac{100}{x}) \times 125 + 20 x --- (1)$

$C'(x) = (-\dfrac{12500}{x^2}) + 20 --- (2)$

At C'(x) = 0

$\dfrac{12500}{x^2} = 20$

$\dfrac{12500}{20} = x^2$

$x^2= 625$

$x = \sqrt{625}$

x = 25

$C'' (x) = -12500 \times \dfrac{-2}{x^3} +0$

$C'' (x) = \dfrac{25000}{x^3}$

where; x = 25

$C'' (x) = \dfrac{25000}{25^3}$

C''(x) = 1.6

Thus, at x = 25, C'' > 0

As such, to minimize the cost, the printer needs to make 25 metal plates.

4 0

3 years ago