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stellarik [79]
3 years ago
5

What is 6,384 times 745

Mathematics
1 answer:
fgiga [73]3 years ago
5 0

Answer:

4756080

Step-by-step explanation:

I hope this helps you

You might be interested in
When planting a garden, 17 out of 25 plants sprout on time.
iogann1982 [59]

Answer:

8/25 or 32%

Step-by-step explanation:

if 17/25 do sprout on time than 8 or the twenty five don't.  So 8/25 is the amount that don't and by multiplying both the top and bottom fraction by 4 you will get 32/100 or 32%

4 0
3 years ago
Anyone got an answer?
Furkat [3]

Answer: I am learning this right now, and the right answer is c

Step-by-step explanation: If you set it up correctly it is going to be a fraction, and d cannot be solved so that leaves you with c.

7 0
3 years ago
Read 2 more answers
Find the value of x.<br><br><br>m∠IHG = 162°<br><br>m∠IHK = (4x + 4)°<br><br>m∠KHG = (8x + 2)°
kirill [66]

Answer:

1

Step-by-step explanation:

<IHG = 162

<IHK = 4x + 4

<KHG = 8x + 2

<IHG + <IHK + <KHG = 180° (sum of angles in a triangle is equal to 180°)

See attachment for better illustration of the triangle

162 + (4x + 4) + (8x + 2) = 180

162 + 4x + 4 + 8x + 2 = 180

168 + 12x = 180

Collect liketerms

12x = 180 - 168

12x = 12

x = 1

7 0
4 years ago
Read 2 more answers
Can you please do 1 to 10
ehidna [41]
1) 4(x-6)<2
2) 7n+19<8
3) 3(11+x)>=15
4) 4n-12<6
5) 2n+14>=1
6) 2(x+7)>=10
7) 11n-3>9
8)8x+4<=13
9)5n+16>=9
10) 4(x+2)<14
3 0
4 years ago
A printer has a contract to print 100,000 posters for a political candidate. He can run the posters by using any number of plate
yulyashka [42]

Answer:

25

Step-by-step explanation:

From the given information;

Numbers of posters that can be printed in an hour = no of impression/hour × no of plate utilized in each impression.

= 1000x

Thus, the required number of hours it will take can be computed as:

\implies \dfrac{100000}{1000x} \\ \\ =\dfrac{100}{x}

cost per hour = 125

If each plate costs $20 to make, then the total number of plate will equal to 40x

∴

The total cost can be computed as:

C(x) = (\dfrac{100}{x}) \times 125 + 20 x --- (1)

C'(x) = (-\dfrac{12500}{x^2})  + 20  --- (2)

At C'(x) = 0

\dfrac{12500}{x^2} = 20

\dfrac{12500}{20} = x^2

x^2= 625

x = \sqrt{625}

x = 25

C'' (x) = -12500 \times \dfrac{-2}{x^3} +0

C'' (x) = \dfrac{25000}{x^3}

where; x = 25

C'' (x) = \dfrac{25000}{25^3}

C''(x) = 1.6

Thus, at x = 25, C'' > 0

As such, to minimize the cost, the printer needs to make 25 metal plates.

4 0
3 years ago
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