Given the two points (3, -1) and (5,3), explain how to write the equation of the line in slope intercept form.

Mathematics

2 answers:

kakasveta [241]3 years ago

7 0

Can you add an image please?

katrin2010 [14]3 years ago

3 0

1. To find slope use the slope equation which would be (3 - -1)/ (5-3). The slope is m = 4\2 which is m = 2

2. Plug in one of the points to find the y-intercept. Using the point (5,3) , you would plug this point into the slope intercept equation, along with the slope which was found. 3= (2 x 5) +b. Solving this equation b=-7

3. The slop intercept form is y = 2x - 7

I hope this is the right answer!

You might be interested in

Find the slope of the line that passes through the points (-1, 1) and (2, 7).

Kruka [31]

Answer:

2 is your slope

Step-by-step explanation:

Find the slope. Use the slope-formula:

m (slope) = (y₂ - y₁)/(x₂ - x₁)

Let:

(x₁ , y₁) = (-1 , 1)

(x₂ , y₂) = (2 , 7)

Plug in the corresponding numbers to the corresponding variables:

m = (7 - 1)/(2 - (-1))

Simplify:

m = (6)/(2 + 1)

m = 6/3

m = 2

2 is your slope (or rise 2, run 1).

6 0

3 years ago

Read 2 more answers

Explain why 58 can be rounded to the nearest hundred even though there is not a digit in the hundreds place?

Mrac [35]

Because 58 is closer to 100 than 0
another example you can see is if it was 10058 and you were asked to round to the nearest hundred you can say 10100

8 0

3 years ago

Read 2 more answers

How do I get this answer?

Keith_Richards [23]

Answer:

Step-by-step explanation:

Several trig identities are involved in the proof of this. This is the order in which they are used.

cos(2x) = cos²(x) -sin²(x)
cos²(x) +sin²(x) = 1
cos(x) = 1/sec(x)

<h3>Proof</h3>

Starting with the left side, we can transform it into the right side.

$2\cos(2x)=2(\cos^2(x)-\sin^2(x)) = 2(\cos^2(x)-(1-\cos^2(x)))\\\\=2(2\cos^2(x)-1)=2\left(\dfrac{2}{\sec^2(x)}-\dfrac{\sec^2(x)}{\sec^2(x)}\right)\\\\=\boxed{\dfrac{4-2\sec^2(x)}{\sec^2(x)}}$