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Margaret [11]
3 years ago
7

What are the solutions to the quadratic equation x^2 + 8x - 8 = 0?

Mathematics
1 answer:
Elanso [62]3 years ago
4 0

Answer:

x=−4+2√6 or x=−4−2√6

E is the answer

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The Tanners just got married and are trying to decide whether to file jointly or separately. They make $75,000 and $28,000. If t
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La respuesta es la C

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Primero tienes que hacer el 25% de ambas cantidades y luego sumarlo

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I really did try man ;-;

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I will give brainliest for question! How many nonzero terms are in the expansion of (x+4)(2x^2+3x+9)-3(x^3-2x^2+7x)?
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Four

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Let's expand and see how many nonzero terms:

⇒ (x+4)(2x²+3x+9)-3(x³-2x²+7x)=

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⇒ - x³ + 17x² - 12x + 12

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4 0
3 years ago
A toy rocket is launched vertically from 5 feet above ground level with an initial velocity of 112 feet per second. The height h
Masja [62]

Answer:

Step-by-step explanation:

a)The height h after t seconds is given by the equation h(t)=-16t^2+112t+5.

Where 5 represents 5feet above the ground and this is the height from which the rocket was launched.

The equation is a quadratic equation. The plot of this equation on a graph would give a parabola whose vertex would be equal to the maximum height travelled by the rocket.

The vertex of the parabola is calculated as follows,

Vertex = -b/2a

From the equation,

a = -16

b = 112

Vertex = - - 112/32= 3.5

So the rocket will attain maximum height at 3.5 seconds.

It will also take 3.5 seconds to reach the ground. This means it will take a total of 3.5 seconds + 3.5 seconds

= 7 seconds to hit the ground.

b) to find time it will take to be 100 feet above the ground,

-16t^2+112t-95 = 0

Using general quadratic equation formula,

a = -16

b = 112

c = -95

t = [-b+/-√b^2-4ac]/2a

t = [ -112 +/-√112^2-4×-16×-95]/16 × -2

= [-112 +/-√12544-6080]/-32

= (-112+80.4)/-32 or (-112-80.4)/-32

t = 0.9875 or t = 6.0125

So it will take 0.9875 or approximately 1 second to be 100 feet above the ground

7 0
3 years ago
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