All categories

2 years ago

What are the solutions to the quadratic equation x^2 + 8x - 8 = 0?

Mathematics

1 answer:

Elanso [62]2 years ago

4 0

Answer:

x=−4+2√6 or x=−4−2√6

E is the answer

You might be interested in

In the figure below, BD bisects ∠ABC. What is the length of AB?

dimaraw [331]

Answer:

D. 12

Step-by-step explanation:

Based on the Angle Bisector theorem, the opposite sides of ∆ABC are divided into proportional segments alongside the two other sides of the triangle, as BD bisects the <ABC. This implies that:

AB/AD = CB/CD

Substitute

AB/8 = 6/4

Cross multiply

AB*4 = 6*8

AB*4 = 48

AB = 48/4

AB = 12

3 0

3 years ago

A parabola has a vertex at (-1,0) and opens down. What is the equation of the parabola?

Lapatulllka [165]

Answer:

y = - (x + 1)²

Step-by-step explanation:

Vertex form of a parabola is given by,

y = -(x - h)² + k

Where (h, k) is the ordered pair representing vertex.

(-) sign denotes that the parabola is opening downwards.

If the coordinates of the given parabola is (-1, 0)

Equation of the parabola will be,

y = - (x + 1)² + 0

y = - (x + 1)²

Therefore, equation of the parabola will be, y = - (x + 1)²

5 0

3 years ago

At a local restaurant, the amount of time that customers have to wait for their food is normally distributed with a mean of 18 m

Colt1911 [192]

Answer:

99.7% of customers have to wait between 8 minutes to 30 minutes for their food.

Step-by-step explanation:

We are given the following in the question:

Mean, μ = 18 minutes

Standard Deviation, σ = 4 minutes

We are given that the distribution of amount of time is a bell shaped distribution that is a normal distribution.

Empirical Formula:

Almost all the data lies within three standard deviation from the mean for a normally distributed data.
About 68% of data lies within one standard deviation from the mean.
About 95% of data lies within two standard deviations of the mean.
About 99.7% of data lies within three standard deviation of the mean.

Thus, 99.7% of the customers have to wait:

$\mu -3\sigma = 18-3(4) = 6\\\mu +3\sigma = 18+3(4) = 30$