Answer:
All are rational.
Step-by-step explanation:
1)
=1/3/3/5
=1/3×5/3
=5/9
5/9 is non-terminating and recurring number so it is rational.
2)
4/3√9/5
=4/3*3/5
=4/5
4/5 is a terminating number it is rational.
3)
2*√16/√4
=2*4/2
=4
4 is a natural/whole number it is also rational.
Note<u>:</u><u>i</u><u>f</u><u> </u><u>y</u><u>o</u><u>u</u><u> </u><u>n</u><u>e</u><u>e</u><u>d</u><u> </u><u>t</u><u>o</u><u> </u><u>a</u><u>s</u><u>k</u><u> </u><u>a</u><u>n</u><u>y</u><u> </u><u>questions</u><u> </u><u>please</u><u> </u><u>l</u><u>e</u><u>t</u><u> </u><u>m</u><u>e</u><u> </u><u>k</u><u>n</u><u>o</u><u>w</u><u>.</u>
The side on the front of 30° is 1/2 of hypytenuse
Then 1/2 of 4=2 and the ather side with theorem of pytagore is squares root of(4^2-2^2)=sq .root of 12
This side(square root of 12) is 1/2 of hypotenuse then
Hypotenuse is 2*square root 12
X^2=(2*sq .root12)^2 -(square root 12)^2
X^2=48-12=36
X=6
Answer:
The mileage of the car is 30 miles per gallon
Step-by-step explanation:
Here, we are interested in calculating the gas mileage of the car.
The gas mileage refers to the number of kilometers the car can travel on a particular amount of fuel.
The full capacity of the car tank is 15 gallon
Now after traveling 300 miles, it stops for gas and 10 gallons of fuel are added to make the car full again.
What this means is that the car used up a total of 10 gallons of fuel for the 300 miles
Thus, the gas mileage of the car is that it used 10 gallons to travel a total of 300 miles
Expressing this as a ratio, we have 300 miles/10 gallons = 30 miles/ gallon
This means that on a gallon of fuel, the car can travel 30 miles
