Answer:
5
Step-by-step explanation:
hope this helps
Answer:
The GCF for the numerical part is 2
Step-by-step explanation:
6x^2y^2-8xy^2+10xy
It contains both numbers and variables, there are two steps to find the GCF(HCF).
1). Find the GCF for the numerical part 6, -8,10
2). Find the GCF for the variable part x^2,y^2,x^1,y^2,x^1,y^3
3).Multiply the values together.
Find the common factors for the numerical part:
6,-8,10
Factors of 6
6: 1,2,3,6
Factors of -8
-8: -8,-4,-2,-1,1,2,4,8
Factors of 10
10:1,2,5,10
Common factors of 6,-8, 10 are 1,2
The GCF Numerical=2
The GCF Variable= xy^2
Multiply the GCF of the numerical part 2 and the GCF of the variable part xy^2, and you'll get 2xy^2
Answer:
All solutions or infinite.
Step-by-step explanation:
Turn 2y = -4x + 6 into standard form - divide by 2
Y = -2x + 3
2x + y = 3
Substitute the y equation in for y.
2x - 2x + 3 = 3
The x variables cancel out.
3 = 3
Which is true so it means all solutions.
Hope this helps.
Step-by-step explanation:
a). A = {x ∈ R I 5x-8 < 7}
5x - 8 < 7 <=> 5x < 8+7 <=> 5x < 15 =>
x < 3 => A = (-∞ ; 3)
A ∩ N = {0 ; 1 ; 2}
A - N* = (-∞ ; 3) - {1 ; 2}
b). A = { x ∈ R I 7x+2 ≤ 9}
7x+2 ≤ 9 <=> 7x ≤ 7 => x ≤ 1 => x ∈ (-∞ ; 1]
A ∩ N = {0 ; 1}
A-N* = (-∞ ; 1)
c). A = { x ∈ R I I 2x-1 I < 5}
I 2x-1 I < 5 <=> -5 ≤ 2x-1 ≤ 5 <=>
-4 ≤ 2x ≤ 6 <=> -2 ≤ x ≤ 3 => x ∈ [-2 ; 3]
A ∩ N = {0 ; 1 ; 2 ; 3}
A - N* = [-2 ; 3) - {1 ; 2}
d). A = {x ∈ R I I 6-3x I ≤ 9}
I 6-3x I ≤ 9 <=> -9 ≤ 6-3x ≤ 9 <=>
-15 ≤ -3x ≤ 3 <=> -5 ≤ -x ≤ 3 =>
-3 ≤ x ≤ 5 => x ∈ [-3 ; 5]
A ∩ N = {0 ; 1 ; 2 ; 3 ; 4 ; 5}
A - N* = [-3 ; 5) - {1 ; 2 ; 3 ; 4}
Answer:
Distance = 70 + 55 = 125 kilometers
Time = 4 + 3 = 7 hours
Rate = Distance / Time
Rate = 125 / 7 = 17.8571428571 kilometers per hour
Step-by-step explanation:
