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ipn [44]
3 years ago
11

A radioactive isotope has a half life of 4.51 days. If 12.63 grams are now present, how much will be left after 15

Mathematics
1 answer:
Marizza181 [45]3 years ago
7 0

Answer:

Step-by-step explanation:

f=ir^t\\ \\ \frac{1}{2}=r^{4.51}\\ \\ ln(0.5)=4.51lnr\\ \\ r=e^{\frac{ln0.5}{4.51}}\\ \\ r\approx 0.8575\\ \\ f(15)=12.63(0.8575^{15}\\ \\ f(15)\approx 1.26g

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Lets call x the amount of 18% solution and y the amount of 40% solution, and write as equations the info of the problem:
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-18x -<span> 18y = -180
</span>----------------------
0 + 22y = 20
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and substitute in the original equation:
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MA_775_DIABLO [31]

Answer:

<h2>$21000</h2>

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This problem is on simple interest calcultion

A=P(1+r*n)

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A=15000(1.4)

A=$21000

<h2>Hence the ending balance that lucy would pay is $21000</h2>
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