All categories

3 years ago

What is the range of this function(–11, 8) (13, 7) (14, 7)

Mathematics

1 answer:

scoray [572]3 years ago

7 0

Answer:

The range is { 7,8}

Step-by-step explanation:

The range of the functions is the output values

We do not list the repeated values more than one and normally list them from smallest to largest

The range is { 7,8}

You might be interested in

Explain how you can rename 5,400 as hundreds.

balandron [24]

Answer:

The correct answer would be 54 hundreds

Step-by-step explanation:

If we are considering how many hundreds something has, we can simply take away two 0's and use that number. We take the two 0's off and then we have the right number of hundreds

7 0

3 years ago

Read 2 more answers

I need help I mark as Brainliesit just please HELP ME RIGHT NOW THIS IS PAST AND NO ONE HASED HELP ME WITH THESE 1-7 QUESTION! y

Luden [163]

Answer:

dang I'm sorry I'm only in middle school but dang that's a lot

4 0

3 years ago

Direction:Determine between what two integers the following square root of a number is. Select the letter of your choice below.

inn [45]

Answer:

jsa-ygso-fxk join girls

7 0

3 years ago

What is the volume of the right triangular prism shown? for brainlist

emmainna [20.7K]

Answer: C

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Find the least common multiple (LCM) of 8y^6+ 144y^5+ 640y^4 and 2y^4 + 40y^3 + 200y^2.

Mice21 [21]

Answer:

LCM = $8y^{4}(y+ 10)^{2}(y + 8)$

Step-by-step explanation:

Making factors of $8y^{6}+ 144y^{5}+ 640y^{4}$

Taking $8y^{4}$ common:

$\Rightarrow 8y^{4} (y^{2}+ 18y+ 80)$

Using factorization method:

$\Rightarrow 8y^{4} (y^{2}+ 10y + 8y + 80)\\\Rightarrow 8y^{4} (y (y+ 10) + 8(y + 10))\\\Rightarrow 8y^{4} (y+ 10)(y + 8))\\\Rightarrow \underline{2y^{2}} \times 4y^{2} \underline{(y+ 10)}(y + 8)) ..... (1)$

Now, Making factors of $2y^{4} + 40y^{3} + 200y^{2}$

Taking $2y^{2}$ common:

$\Rightarrow 2y^{2} (y^{2}+ 20y+ 100)$

Using factorization method:

$\Rightarrow 2y^{2} (y^{2}+ 10y+ 10y+ 100)\\\Rightarrow 2y^{2} (y (y+ 10) + 10(y + 10))\\\Rightarrow \underline {2y^{2} (y+ 10)}(y + 10) ............ (2)$

The underlined parts show the Highest Common Factor(HCF).

i.e. HCF is $2y^{2} (y+ 10)$ .

We know the relation between LCM, HCF of the two numbers 'p' , 'q' and the numbers themselves as:

$HCF \times LCM = p \times q$

Using equations (1) and (2): $\Rightarrow 2y^{2} (y+ 10) \times LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times 2y^{2} (y+ 10)(y + 10)\\\Rightarrow LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times (y + 10)\\\Rightarrow LCM = 8y^{4}(y+ 10)^{2}(y + 8)$

Hence, LCM = $8y^{4}(y+ 10)^{2}(y + 8)$

5 0

3 years ago